Capitolul 1: Bancuri de filtre
Capitolul 1: Bancuri de filtre
Capitolul 1: Bancuri de filtre
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PAS cap. 1: <strong>Bancuri</strong> <strong>de</strong> <strong>filtre</strong> – p. 34/75<br />
Condiţie pe componentele polifază<br />
• Scriem H 0 (z) = H 00 (z 2 ) + z −1 H 01 (z 2 )<br />
• Filtrul produs capată forma<br />
P(z) = H 00 (z 2 )H 00 (z −2 ) + H 01 (z 2 )H 01 (z −2 )<br />
+z −1 H 01 (z 2 )H 00 (z −2 ) + zH 00 (z 2 )H 01 (z −2 )<br />
• Primii doi termeni conţin puterile impare, <strong>de</strong>ci condiţia <strong>de</strong><br />
RP este<br />
P 0 (z) <strong>de</strong>f = H 00 (z)H 00 (z −1 ) + H 01 (z)H 01 (z −1 ) = 1 (8)