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Capitolul 1: Bancuri de filtre

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PAS cap. 1: <strong>Bancuri</strong> <strong>de</strong> <strong>filtre</strong> – p. 18/75<br />

Reprezentarea polifază<br />

• Consi<strong>de</strong>răm M = 2<br />

• Fie G(z) un filtru, pe care îl scriem folosind componentele<br />

polifază<br />

G(z) = G 0 (z 2 ) + z −1 G 1 (z 2 )<br />

• Exemplu: dacă G(z) = 1 + 2z −1 + 3z −2 + 4z −3 , atunci<br />

G 0 (z) = 1 + 3z −1 şi G 1 (z) = 2 + 4z −1<br />

• Filtrul poate fi implementat prin schema echivalentă<br />

✲<br />

G(z)<br />

✲<br />

⇐⇒<br />

✲ G 0 (z 2 )<br />

❄<br />

z −1<br />

✲ G 1 (z 2 )<br />

✲❄<br />

• Deocamdată nu rezultă nici un avantaj, ba dimpotrivă

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