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Culegere de probleme de Analiz˘a numeric˘a

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Capitolul 5<br />

Calculul cu diferent¸e<br />

Să consi<strong>de</strong>răm mult¸imea<br />

M = {ak|ak = a+kh, k = 0,m, a,h ∈ R}<br />

Definit¸ia 5.0.6 Pentruf : M → R, cantitatea<br />

∆hf(ai) = f(ai +h)−f(ai), i < m<br />

se numes¸te diferent¸a finită <strong>de</strong> ordinul I cu pasulhafunct¸iei f în punctulai.<br />

Diferent¸a finită <strong>de</strong> ordinulk se <strong>de</strong>fines¸te recursiv prin<br />

Au loc relat¸iile<br />

∆ m h<br />

∆ m h<br />

f(a) =<br />

∆ k hf(ai) = ∆n(∆ k−1<br />

h f(ai))<br />

f(a) =<br />

∆ m h (fg)a =<br />

m<br />

(−1) i<br />

<br />

m<br />

f[a+(m−i)h]<br />

i<br />

i=0<br />

m<br />

(−1) m−i<br />

<br />

n<br />

f(a+ih)<br />

i<br />

i=0<br />

f(ak) =<br />

m<br />

k<br />

i=0<br />

m<br />

i<br />

<br />

k<br />

∆<br />

i<br />

i hf(a)<br />

<br />

∆ i hf(a)∆ m−i<br />

h g(a+ih)<br />

i=0<br />

Valorile[∆m 1 xr ]x=0 = ∆m0r se numesc diferent¸ele lui 0.<br />

∆ m 0 r =<br />

m<br />

(−1) m−i<br />

<br />

m<br />

i<br />

i<br />

r<br />

i=0<br />

67

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