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Culegere de probleme de Analiz˘a numeric˘a

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2.4. Polinoame ortogonale 31<br />

(1) Arătat¸i că<br />

(2)<br />

(3)<br />

(4)<br />

(5)<br />

(6)<br />

(7)<br />

(8)<br />

l α n ∈ Pn s¸i 〈l α n ,lα Γ(n+α+1)<br />

m 〉 =<br />

n!<br />

(înL2 w(0,∞) cuw(x) = xαe−x ) un<strong>de</strong>Γ(s) este funct¸iaΓalui Euler <strong>de</strong>finită<br />

prin<br />

Γ(s) =<br />

∞<br />

t<br />

0<br />

s−1 e −t dt (s > 0)<br />

nl α n (x)−(2n−1+α−x)lα n−1 (x)+(n−1−α)lα n−2 (x) = 0<br />

l α+1<br />

n (x)−l α+1<br />

n−1 (x) = lα n (x)<br />

d<br />

dx lα n(x) = −l α+1<br />

n−1(x), x d<br />

dx lα n(x) = nl α n(x)−(n+α)l α n−1(x)<br />

∞<br />

n=0<br />

l α n (x) =<br />

x n<br />

n! =<br />

t n l α n (x) =<br />

n<br />

(−1) k<br />

<br />

n+α<br />

x<br />

n−k<br />

k /k!<br />

k=0<br />

n<br />

(−1) k<br />

<br />

n+α<br />

l<br />

n−k<br />

α k<br />

k=0<br />

1 xt<br />

1−t |t| < 1 (f.gen.)<br />

(1−t) α+1e−<br />

H2n(x) = (−1) n 2 2n n!l −1/1<br />

n (x 2 )<br />

H2n+1(x) = (−1) n 2 2n+1 n!xl 1/2<br />

n (x2 )<br />

Solut¸ie. (1)-(7) se <strong>de</strong>duc utilizând tehnici analoage celor din exercit¸iile prece<strong>de</strong>nte.<br />

(8) se obt¸ine <strong>de</strong>zvoltând în serieHn(x) s¸il α n(x).<br />

Problema 2.4.11 (Ecuat¸ia diferent¸ială verificată <strong>de</strong> polinoamele ortogonale) Fie<br />

w o funct¸ie pozitivă pe[a,b] astfel încât<br />

w ′ (x)<br />

w(x) =<br />

A0 +A1x<br />

B0 +B1x+B2x 2<br />

s¸i lim<br />

x→a+<br />

w(x)(B0 +B1x+B2x<br />

(sau x→b−)<br />

2 ) = 0<br />

(2.35)<br />

(B0+B1x+B2x 2 )p ′′ n +(A0+A1x+B1+B2x)p ′ n −(A1n+B2n(n+1))pn = 0 (2.36)

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