20.07.2013 Views

Culegere de probleme de Analiz˘a numeric˘a

Culegere de probleme de Analiz˘a numeric˘a

Culegere de probleme de Analiz˘a numeric˘a

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

22 Elemente <strong>de</strong> Analiză funct¸ională s¸i teoria aproximării<br />

Deci Ui se <strong>de</strong>termină până la o constantă multiplicativă:<br />

pi(t) = Ai<br />

w(t) U(i)<br />

i (t)<br />

ConstantaAi se poate <strong>de</strong>termina impunând condit¸ii suplimentare, <strong>de</strong> exemplu<br />

ortonormalitate b<br />

w(t)p 2 i(t)dt = 1<br />

a<br />

pn(x) = (x−2n)pn−1(x)−µnpn−2(x)<br />

µn =<br />

pn−1 2<br />

pn−22, λn = 〈xpn−1,pn−1〉<br />

pn−12 Problema 2.4.2 Polinoamele Cebîs¸ev <strong>de</strong> spet¸a I<br />

Stabilit¸i proprietăt¸ile următoare:<br />

Tn(x) = cosnarccosx<br />

Tn+1(x)−2xTn(x)+Tn−1(x) = 0 (2.19)<br />

Tn(Tn(x)) = Tnm(x) = Tm(Tn(x)) (2.20)<br />

Tn(2x 2 −1) = 2Tn(x) 2 −1 (2.21)<br />

Tn(x)Tm(x) = 1<br />

2 (Tn+m(x)+Tm−n(x)), dacă m ≥ n (2.22)<br />

<br />

Tn(x)dx = 1<br />

<br />

Tn+1(x) Tn−1(x)<br />

− , dacă n > 1 (2.23)<br />

2 n+1 n−1<br />

Tn(x) = 1<br />

2 (Qn(x)−Qn−2(x)) dacă Qn(x) = sin(n+1)θ<br />

;<br />

sinθ<br />

(2.24)<br />

cu x = cosθ (polinom Cebîs¸ev <strong>de</strong> spet¸a a II-a)<br />

2 n−1 x n = <br />

<br />

n<br />

Tn−2k(x), n ≥ 1<br />

k<br />

(2.25)<br />

∞<br />

t n Tn(x) =<br />

m=0<br />

∞<br />

t n Un(x) =<br />

n=0<br />

0≤k≤ n<br />

2<br />

d<br />

dx Tn(x) = nUn−1(x), n ≥ 1 (2.26)<br />

1−xt<br />

1−2xt+t 2,<br />

pentru |t| < 1 (funct¸ia generatoare) (2.27)<br />

1<br />

1−2xt+t 2, pentru |t| < 1, |x| < 1 (2.28)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!