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Culegere de probleme de Analiz˘a numeric˘a

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6.6. Interpolare spline 99<br />

s3(x) = − 1<br />

2 x+2<br />

<br />

x 3 <br />

+ −2 x− 1<br />

3 +(x−1)<br />

2<br />

3 <br />

+<br />

Pentru rest folosim teorema lui Peano<br />

ϕ(x,t) =<br />

(Rf)(x) =<br />

b<br />

<br />

1<br />

(x−t)<br />

(m−1)!<br />

m−1<br />

+ −<br />

= (x−t)+ −<br />

a<br />

ϕ(x;t)f (m) (t)dt<br />

3<br />

<br />

si(x)(xi −t)+ =<br />

i=1<br />

3<br />

si(x)(xi −t)+ =<br />

i=1<br />

<br />

1<br />

= (x−t)+ −s1(x)(−t)+ −s2(x)<br />

2 −t<br />

<br />

+<br />

−s3(1−t)+<br />

Problema 6.6.3 Fie funct¸ia f(x) = sinπx s¸i nodurile x0 = 0, x1 = 1<br />

6 , x2 =<br />

1<br />

2 , x3 = 1.<br />

Să se <strong>de</strong>termine o funct¸ie spline naturală s¸i o funct¸ie spline limitată (racordată)<br />

care aproximează pef.<br />

Solut¸ie. Vom rezolva un sistem liniar <strong>de</strong> formaAx = b.<br />

Pentru funct¸ia spline naturală avem:<br />

⎡<br />

⎢<br />

A = ⎢<br />

⎣<br />

1 0 0 ... ... 0<br />

h0 2(h0 +h1) h1 ... ... 0<br />

0 h1 2(h1 +h2) h2 ... 0<br />

... ... ... ... ... ...<br />

... ... hn−2 2(hn−1 +hn+1) hn−1<br />

0 ... ... 0 0 1<br />

⎡<br />

⎢<br />

b = ⎢<br />

⎣<br />

3<br />

hn−1<br />

0<br />

3<br />

(an −a1)− 3<br />

(a1 −a0)<br />

h1<br />

h0<br />

.<br />

(an −an−1)− 3<br />

0<br />

(an−1 −an−2)<br />

hn−2<br />

⎤<br />

⎥<br />

⎥.<br />

⎥<br />

⎦<br />

⎤<br />

⎥<br />

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