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Subiecte licenta 2013 ISAPM

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ui<br />

− u f<br />

U = mi<br />

⋅<br />

100 − u<br />

f<br />

40 − 6<br />

= 1300 ⋅ =<br />

100 − 6<br />

470.<br />

2<br />

kg<br />

m f = mi<br />

−U<br />

= 1300 − 470.<br />

2 = 829.<br />

8<br />

h<br />

b) Debitul de aer se calculează ca produs între consumul specific (l) i debitul de umiditate (U):<br />

L = l ⋅U<br />

= 65 ⋅ 470.<br />

2 = 30563 kg h<br />

c) Căldura necesară încălzirii aerului în calorifer:<br />

30563<br />

Qnec = L ⋅(<br />

H fin − H in ) = ⋅(<br />

150 − 80)<br />

= 594.<br />

3 kW .<br />

3600<br />

kg<br />

h<br />

60

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