NBR 6118
NBR 6118
NBR 6118
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VigasExemploSeção TransversalMateriais•f ck =25MPa•Aço CA50Módulo 4a) Dimensionamentoa.1) Armadura LongitudinalMkM = γ × Md= 148,5KNm.M = 1,40×M = 207,90 KN.md28×=68f2kk⎡x = 1,25d⎢1−⎣⎡⎢x = 1,25.45⎢1−⎢⎢⎣x = 6,19cmMd1−0,425bdf2cd⎤⎥⎦⎤20790 ⎥1−⎥2 2,50,425.65.45 . ⎥1,4 ⎥⎦<strong>NBR</strong> <strong>6118</strong> PROJETO DE ESTRUTURAS DE CONCRETO : PROCEDIMENTO D A T A 0 0 / 0 0 / 0 0VigasMódulo 4Exemploa) DimensionamentoAs=σ20790As=50(45 − 0,4.6,19)1,15A = 11,24cm²ssdb S= 9 cm (c = 1,5 cm e φ t= 5 mm)b S− 3⋅φe =lh2Md(d − 0,4x)6 φ 16,0 mm9 − 3⋅1,60e = = cm ⎜⎛ 3 16. 0h 2,10φ2⎝ camada⎟⎞⎠<strong>NBR</strong> <strong>6118</strong> PROJETO DE ESTRUTURAS DE CONCRETO : PROCEDIMENTO D A T A 0 0 / 0 0 / 0 0
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