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Folha de Rosto - Sistemas SET - USP

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Capítulo 4-Estratégias <strong>de</strong> Enriquecimento<br />

1( ξη , ) 1 ⎡<br />

( ξη ,<br />

⎢<br />

) ⎣<br />

y<br />

η<br />

1( ξη , )<br />

ξ<br />

y<br />

ξ<br />

1(<br />

ξη , ) ⎤<br />

η<br />

⎥<br />

⎦<br />

1( ξη , ) 1 ⎡<br />

( ξη ,<br />

⎢<br />

) ⎣<br />

x<br />

η<br />

1( ξη , )<br />

ξ<br />

x<br />

ξ<br />

1(<br />

ξη , ) ⎤<br />

η<br />

⎥<br />

⎦<br />

( 00 , ) 1 ⎡<br />

( 00 ,<br />

⎢<br />

) ⎣<br />

y<br />

η<br />

( 00 , )<br />

ξ<br />

y<br />

ξ<br />

( 00 , ) ⎤<br />

η<br />

⎥<br />

⎦<br />

( 00 , )<br />

=<br />

1<br />

( 00 , )<br />

∂x ∂N1 −<br />

( 00 , ) ∂x<br />

∂N1<br />

+<br />

( 00 , )<br />

∂ ∂N ∂ ∂N ∂ ∂N<br />

N1 = N1,<br />

x = = −<br />

∂x ∂x J ∂ ∂ ∂ ∂<br />

∂ ∂N ∂ ∂N ∂ ∂N<br />

N1 = N1,<br />

y = = − +<br />

∂y ∂y J ∂ ∂ ∂ ∂<br />

0<br />

enriq enriq enriq<br />

∂ enriq 1 ∂ 1 ∂ 1<br />

N1<br />

= = −<br />

enriq<br />

1<br />

∂N ∂N ∂N<br />

∂x ∂x J ∂ ∂ ∂ ∂<br />

0<br />

∂<br />

N<br />

∂x<br />

∂N<br />

=<br />

⎡ ⎤<br />

∂y J<br />

⎢<br />

∂η ∂ξ ∂ξ ∂η<br />

⎥<br />

⎣ ⎦<br />

enriq<br />

1<br />

enriq enriq<br />

83<br />

(4.35)<br />

Agora, voltando a analisar a estrutura das equações (4.11), substituindo-se<br />

diretamente nas mesmas as equações (4.7), obtém-se as <strong>de</strong>finições (4.36):<br />

T T −1 T T −1<br />

T<br />

K = B S( S S) S ES( S S) S BdV<br />

Ve<br />

Γ=<br />

=<br />

∫<br />

∫<br />

( ) ( )<br />

iT T −1 T T −1<br />

T<br />

B SSS SESSS SBdV<br />

Ve<br />

∫<br />

( ) ( )<br />

iT T −1 T T −1<br />

T i<br />

Q B S S S S ES S S S B dV<br />

Ve<br />

(4.36)<br />

Po<strong>de</strong>-se introduzir uma representação mais con<strong>de</strong>nsada para as equações<br />

(4.36) da seguinte forma:<br />

e,<br />

representadas como:<br />

=<br />

T<br />

K B EBdV<br />

V<br />

Γ=<br />

=<br />

∫<br />

∫<br />

∫<br />

iT<br />

B EBdV<br />

V<br />

iT i<br />

Q B EB dV<br />

V<br />

T −1<br />

T<br />

B = SSS ( ) SB<br />

B = SSS ( ) SB<br />

i T −1<br />

T i<br />

Realizando-se as operações indicadas, as matrizes B e<br />

⎡N 0 N 0 N 0 N 0 ⎤<br />

1, x 2, x 3, x 4, x<br />

⎢ ⎥<br />

= ⎢ 0 1, y 0 2, y 0 3, y 0 4, y⎥<br />

B N N N N<br />

⎢N N N N N N N N ⎥<br />

⎣ 1, y 1, x 2, y 2, x 3, y 3, x 4, y 4, x⎦<br />

(4.37)<br />

(4.38)<br />

i<br />

B po<strong>de</strong>m ser<br />

(4.39)

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