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9<br />
NBA<br />
3º Passo Método dos Nós<br />
Nó “A” Forças Verticais (V) Forças Verticais (H)<br />
9 NAB NAB<br />
NBC<br />
ΣFV = 0 ΣFH = 0<br />
NAC = 0 -9+NAB = 0<br />
NAB = 9 KN<br />
Nó “B” Forças Verticais (V) Forças Verticais (H)<br />
= 0<br />
ΣFV = 0 ΣFH = 0<br />
-NBD-NBC.sen36,87°=0 -NBA-NBC = 0<br />
-NBD-(-11,25).sen36,87°=0 -NBA-NBC.cos36,87°=0<br />
-NBD+6,75=0 -9-NBC.cos36,87°<br />
NBD = 6,75 KN NBC = -9÷cos36,87°<br />
NBC = -11,25 KN<br />
Nó “C” Forças Verticais (V) Forças Verticais (H)<br />
NC<br />
NCE<br />
ΣFV = 0 ΣFH = 0<br />
NCA-NCE+NCB.sen36,87° = 0 -<br />
9+NCB.cos36,87°+NCD = 0<br />
0-NCE+(-11,25).sen36,87° = 0 -9+(-<br />
11,25).cos36,87°+NCD = 0<br />
0<br />
NA<br />
NBD<br />
NCB<br />
NC<br />
NA<br />
NBC NBD<br />
NC NCB<br />
NCE<br />
9<br />
NBA<br />
NBC<br />
9<br />
NCB<br />
NCE = -6,75 KN -9-9+NCD =<br />
NC<br />
NCD = 18 KN<br />
34
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