Apostila de Treliças 2

NCB
NG
NGF
= 0
“1” NBC-NBG = 0 NBC-NBG = 0
“2” NBC+NBG= -8 -4 - NBG = 0
2NBC = -8 NBG = -4 KN
NBC = -8÷2
NBC = -4 KN
Nó “C” Forças Verticais (V) Forças Verticais (H)
ΣFV = 0 ΣFH = 0
-NCB.sen30°-NCD.sen30°-NCG = 0 -
NCB.cos30°+NCD.cos30° = 0
0
3,5÷cos30°
-(-4).sen30°-(-4).sen30°-NCG = 0 -(-4).cos30°+NCD.cos30° =
2 + 2- NCG = 0 3,5+NCD.cos30°
NCG = 4 KN NCD = -
NCD = -4 KN
Nó “G” Forças Verticais (V) Forças Verticais (H)
NGF+NGH = 0
6,9+NGH = 0
6,9+NGH = 0
KN
NC
NG
NC
NG
NG
+
NCB NC NC
NG NG NG
ΣFV = 0 ΣFH = 0
NGB.sen30°+NGC+NGD.sen30° = 0 -NGB.cos30°+NGD.cos30°-
-4.sen30°+4+NGD.sen30° = 0 -(-4).cos30°+(-4).cos30°-
NCB
NGD = -2÷sen30 +3,5-3,5-
NG
NGF
NGD = -4 KN NGH = 6,9
NC
NG
NG
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