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Apostila de Treliças 2

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2.n = b+ν<br />

2.5 = 7+3<br />

10 = 10 OK<br />

2º Passo Reações <strong>de</strong> Apoio<br />

ΣFx = 0 ΣFy = 0 ΣM = 0 (Momento<br />

fletor)<br />

HA+HB = 0 VA = 225 -HB.0,9+75.2,4+150.1,2 = 0<br />

HB = -HA HB = 360÷0,9<br />

HA = - 400 KN HB = 400 KN<br />

3º Passo Método dos Nós<br />

Nó “B” Forças Verticais (V) Forças Verticais (H)<br />

NBA<br />

HB HB<br />

NBD<br />

ΣFV = 0 ΣFH = 0<br />

NBA = 0 HB+NBD = 0<br />

400+NBD = 0<br />

NBD = -400 KN<br />

Nó “A” Forças Verticais (V) Forças Verticais (H)<br />

VA<br />

HA HA<br />

NA<br />

NAB<br />

NA<br />

NAB<br />

NBA<br />

VA<br />

NA<br />

ΣFV = 0 ΣFH = 0<br />

VA-NAB-NAD.sen36,87° = 0 -<br />

HA+NAC+NAD.cos36,87° = 0<br />

225-0-NAD.sen36,87° = 0 -<br />

400+NAC+375.cos36,87 = 0<br />

NBD<br />

NA<br />

NA<br />

22

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