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Apostila de Treliças 2

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ND<br />

NDE<br />

NBE<br />

3,13.sen53,13°+NED.sen53,13° = 0 -9,38+NEB+(-3,13).cos53,13°-<br />

(+3,13).cos53,13° = 0<br />

0<br />

NBD<br />

NED = -2,5÷sen53,13° NEB-9,38-1,88-1,88 =<br />

NED = -3,13 KN NEB = 13,14 KN<br />

Nó “D” Forças Verticais (V) Forças Verticais (H)<br />

20<br />

ΣFV = 0 ΣFH = 0<br />

-20-NDE.sen53,13°-NDB.sen53,13°=0 -NDE.cos53,13°-<br />

NDC+NDB.cos53,13°=0<br />

-20-(-3,13).sen53,13°-NDB.sen53,13°=0 -(-3,13).cos53,13°-(-11,26)+(-<br />

21,88).cos53,13°=0<br />

= 0<br />

-20+2,50-NDB.sen53,13° = 0 1,88+12,26-13,13<br />

NDB = -17,50÷sen53,13° 0 = 0<br />

NDB = -21,88 KN<br />

Nó “B” Forças Verticais (V) Forças Verticais (H)<br />

VB<br />

NDB<br />

13,14 = 0<br />

BARRA<br />

20<br />

NDE NDB<br />

NBD<br />

VB<br />

ΣFV = 0 ΣFH = 0<br />

VB+NBD.sen53,13° = 0 -NBD.cos53,13°-NBE = 0<br />

17,5+(-21,88).sen53,13° = 0 -(-21,88).cos53,13°-<br />

0 = 0 0 = 0<br />

FORÇAS NORMAIS<br />

AXIAIS (KN)<br />

ND<br />

NDE<br />

NBD<br />

NBE<br />

NDB<br />

ESFORÇO<br />

20

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