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3º Passo Método dos Nós<br />
Nó “A” Forças Verticais (V) Forças Verticais (H)<br />
VA<br />
VA+NAC.sen53,13° = 0<br />
HA+NAE+NAC.cos53,13° = 0<br />
15,63).cos53,13° = 0<br />
ΣFV = 0 ΣFH = 0<br />
12,5+NAC.sen53,13° = 0 0+NAE+(-<br />
NAC = -12,5÷sen53,13° NAE = 9,38 KN<br />
NAC = -15,63 KN<br />
Nó “C” Forças Verticais (V) Forças Verticais (H)<br />
ΣFV = 0 ΣFH = 0<br />
-10-NCA.sen53,13°-NCE.sen53,13°=0 -<br />
NCA.cos53,13°+NCD+NCE.cos53,13°=0<br />
-10-(-15,63).sen53,13°-NCE.sen53,13°=0 -(-<br />
15,63).cos53,13°+NCD+3,13.cos53,13°=0<br />
= 0<br />
KN<br />
NA<br />
HA HA<br />
NAE<br />
NC<br />
NEA<br />
NEC<br />
10<br />
NCE<br />
NC<br />
-10+12,50-NCE.sen53,13° = 0 9,38+NCD+1,88<br />
NCE = 2,5÷sen53,13° NCD = -11,26<br />
NCE = 3,13 KN<br />
NA<br />
VA<br />
Nó “E” Forças Verticais (V) Forças Verticais (H)<br />
NED<br />
NEB<br />
10<br />
NC NCE<br />
NEC NED<br />
ΣFV = 0 ΣFH = 0<br />
NEC.sen53,13°+NED.sen53,13° = 0 -NEA+NEB+NED.cos53,13°-<br />
NEC.cos53,13° = 0<br />
NC<br />
NEC<br />
NEA<br />
NA<br />
NAE<br />
NC<br />
NCE<br />
NED<br />
NEB<br />
19
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