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<strong>nye</strong> <strong>MEGA</strong> <strong>–</strong> <strong>fasit</strong><br />
2.6 (6p)<br />
a) konstruksjon b) B = 52,5° Δ ABC er likebent fordi AB = AC.<br />
Da er C = B.<br />
c), d) konstruksjon e) ACE = 15° fordi 180° <strong>–</strong> 75° <strong>–</strong> 90° = 15°<br />
17 15 2 3<br />
2.7 (3p) 225% 2 2,324 2<br />
8 7<br />
7<br />
8<br />
2.8 (2p) 2 2 3 5 7<br />
2.9 (2p) <strong>–</strong>1<br />
2.10 (2p) a) 46<br />
b) 46 har to siffer,<br />
både 4 og 6 er partall,<br />
4 6,<br />
6 <strong>–</strong> 4 = 2, 2 5<br />
4 + 6 = 10<br />
3FASIT <strong>–</strong> Terminprøver høst 2009 <strong>nye</strong> <strong>MEGA</strong> 3
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