Meetsystemen

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Meetsystemen Formularium Ultrasoon: Z E (p)= V(p) i m (p) = V F Q = mk = 1 b 2ζ • x F • i m x = 1 ⎛ (Sk) 2 ⎝ mp + b + p k ⎞ ⎠ ≡ L 1p + R 1 + 1 C 1 p H(p)= C 1L 1p 2 + C 1R 1p + 1 CC 1L 1p 3 + CC 1R 1p 2 + (C 1 + C)p ≅ 1 − C 1L 1ω 2 + jC 1R 1ω −CC 1R 1ω 2 + jω[(C 1 + C) − CC 1L 1ω 2 ] c = f.λ, c = elasticiteitsmodulus ρ , Z A = P u ≅ cρ , Z 1 -Z 2 / Z 1 + Z 2 T t = 2l c , f = f 0 (1 - kt), l = c∆t 2 = c∆ f 2kf 0 f = f c + c v , f = f c − v totale afstand c , λ = =λ c − v , aantal cycli c 2f cos θ ∆f ≅ c , λ =λ c + v c v V som = V sin 2πf t + V sin 2πft= 2V cos 2π( f − f ) t sin 2π( f 2 + f ) t 2 Positie: k a = ingangsversnelling fout op uitgangshoek [t−2 ] φ 1 ~ U 1 = U 0 cosα en φ 2 ~ U 2 = U 0 sinα : U r = U r0 sin(δ - α) Druk: P = F/S, 1 bar = 100.000 Pa [= N/m²] of 10 N/cm². 1 atm = 9,87.E-6 Pa = 760 Torr [mmKK] Temperatuur: T C = 5/9 . (T F - 32) en 0 Kelvin = -273,16 °C R(T)=R 0 (1 +αT +βT 2 + .. . ) , σ = (n.µ n + p.µ p )q, n 2 i = A 0 T 3 e −Ego/kT R = R 0 e β(1/T−1/T 0) I = I r ⎛ ⎝ e qV kT − 1 ⎞ ⎠ , V =( kT q )ln( I ) I r k = 8,62.10 -5 eV/K , q = 1,602.10 -19 C, 1 eV = 1,602.10 -19 J ∆V =α s ∆T , E = C 1 (T 1 − T 2 )+C 2 (T 2 1 − T 2 2 ) Debiet: m = ρV, Q m =ρQ , PV V = nR = cte, T υ=η ρ , Re = vD υ = vDρ η p + 1 , , , 2 ρv2 +ρgh = cte Q = A 2 k ∆p k = 2 ρ ⎛ ⎝ 1 − A 2 /A 2⎞ 1⎠ Q = CA 2 k ∆p f = S. v 1 d , → F c = 2m ⎛ → → ⎝ ω× v ⎞ ⎠ _________ - F.2 - Johan Baeten

Meetsystemen Formularium Overige: sin (x + y) = sin x cos y + cos x sin y cos(x + y) =cos x cos y − sin x sin y tan x + tan y tan (x + y) = 1 − tan x tan y en sin x + sin y sin x − sin y = 2sin x+y x−y cos 2 2 = 2cos x+y 2 cos x + cos y = 2cos x+y 2 cos x − cos y =−2sin x+y 2 sin x−y 2 cos x−y 2 sin x−y 2 1 , indien x

<strong>Meetsystemen</strong><br />

Formularium<br />

Ultrasoon:<br />

Z E (p)= V(p)<br />

i m (p) = V F<br />

Q =<br />

mk = 1 b 2ζ<br />

•<br />

x<br />

F<br />

•<br />

i m x = 1 ⎛<br />

(Sk) 2 ⎝<br />

mp + b +<br />

p k ⎞ ⎠ ≡ L 1p + R 1 + 1<br />

C 1 p<br />

H(p)=<br />

C 1L 1p 2 + C 1R 1p + 1<br />

CC 1L 1p 3 + CC 1R 1p 2 + (C 1 + C)p ≅ 1 − C 1L 1ω 2 + jC 1R 1ω<br />

−CC 1R 1ω 2 + jω[(C 1 + C) − CC 1L 1ω 2 ]<br />

c = f.λ, c = elasticiteitsmodulus<br />

ρ<br />

, Z A = P u ≅ cρ , Z 1<br />

-Z 2<br />

/ Z 1<br />

+ Z 2<br />

T t = 2l<br />

c , f = f 0<br />

(1 - kt),<br />

l = c∆t<br />

2 = c∆ f<br />

2kf 0<br />

f = f c + c<br />

v , f = f c − v totale afstand<br />

c , λ = =λ c − v ,<br />

aantal cycli c<br />

2f cos θ<br />

∆f ≅<br />

c ,<br />

λ =λ c + v<br />

c<br />

v V som = V sin 2πf t + V sin 2πft= 2V cos 2π( f − f ) t sin 2π( f<br />

2<br />

+ f ) t<br />

2<br />

Positie:<br />

k a = ingangsversnelling<br />

fout op uitgangshoek [t−2 ]<br />

φ 1<br />

~ U 1<br />

= U 0<br />

cosα en φ 2<br />

~ U 2<br />

= U 0<br />

sinα : U r<br />

= U r0<br />

sin(δ - α)<br />

Druk:<br />

P = F/S, 1 bar = 100.000 Pa [= N/m²] of 10 N/cm². 1 atm = 9,87.E-6 Pa = 760 Torr [mmKK]<br />

Temperatuur:<br />

T C<br />

= 5/9 . (T F<br />

- 32) en 0 Kelvin = -273,16 °C<br />

R(T)=R 0 (1 +αT +βT 2 + .. . ) , σ = (n.µ n<br />

+ p.µ p<br />

)q, n 2 i = A 0 T 3 e −Ego/kT<br />

R = R 0 e β(1/T−1/T 0)<br />

I = I r<br />

⎛<br />

⎝ e qV<br />

kT − 1 ⎞ ⎠<br />

, V =( kT q )ln( I )<br />

I r<br />

k = 8,62.10 -5 eV/K , q = 1,602.10 -19 C,<br />

1 eV = 1,602.10 -19 J<br />

∆V =α s ∆T , E = C 1 (T 1 − T 2 )+C 2 (T 2 1 − T 2 2 )<br />

Debiet:<br />

m = ρV, Q m =ρQ ,<br />

PV<br />

V = nR = cte, T υ=η ρ<br />

, Re = vD υ = vDρ<br />

η<br />

p + 1 , , ,<br />

2 ρv2 +ρgh = cte Q = A 2 k ∆p k =<br />

2<br />

ρ ⎛ ⎝ 1 − A 2<br />

/A<br />

2⎞<br />

1⎠ Q = CA 2 k ∆p<br />

f = S. v 1<br />

d<br />

,<br />

→<br />

F c = 2m ⎛ → →<br />

⎝ ω× v ⎞<br />

⎠<br />

_________ - F.2 -<br />

Johan Baeten

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