fiets – bromfietstechniek - Fietstoeren

6) Toepassingen: (oplossingen)
F01.Mechanica.
a) 14 = X 14 x X = 14 x 15 = X 210 = 10 X = 10
21 15 21 15 21 21
25 = 35 25 x 35 = 20 x 35 = X 700 = 28 X = 28
20 X 20 X 25 25
X = 90 X x 90 = 100 x 90 = X 9000 = 6 X = 6
100 1500 100 1500 1500 1500
b) 1200 x 3 = 3600 = 36 toeren.
100 100
c) 40 x 100 = 2,5%
100
d) 1,2 km = 1,2 x 1000 = 1200 m
52 dam = 52 x 10 = 520 m
6,5 hm = 6,5 x 100 = 6500 m
12500 cm = 12500 : 100 = 125 m
e) 2 h 5 min 30 s = 2 x 3600 + 300 + 30 = 7530
4 h 18 min 7 s = 4 x 3600 + 18 x 60 + 7
=14400 + 1080 + 7 = 15487
f) 7886 s = 7886 : 3600 = 2 h 11 min
2843 s = 2843 : 3600 = 0 h
2843 : 60 = 47 min x 60 = 2820
2843 – 2820 = 23
g) 45 min = 0,75 h
30 sec = 0,05 h
126 min = 2,1 h
72 sec = 0,12 h
h) 2,27 h = 2 h, 27 x 100 = 270 = 45 = 2h 4
60 6
0,15 h =
3