6. Zuren en basen

6. Zuren en basen 6. Zuren en basen

10.09.2013 Views

Waterconstante • H 2O + H 2O OH - + H 3O + K c = [OH - ] e.[H 3O + ] e /[H 2O] e² = 10 -7 mol/l x 10 -7 mol/l / (55,5 mol/l)² = 3,25.10 -18 (⇒ evenwicht naar links) • [H 2O] e = 55,5 mol/l (cte) ⇒ K w = [OH - ] e.[H 3O + ] e = 10 -7 mol/l x 10 -7 mol/l = 10 -14 (Waterconstante) • pK w = -log K w = 14 = pH + pOH

Zuurtegraad [H 3O + ] pH pOH [OH - ] oplossing 1 mol/l 0 14 10 -14 mol/l zuur 10 -1 mol/l 1 13 10 -13 mol/l 10 -2 mol/l 2 12 10 -12 mol/l 10 -3 mol/l 3 11 10 -11 mol/l 10 -4 mol/l 4 10 10 -10 mol/l 10 -5 mol/l 5 9 10 -9 mol/l 10 -6 mol/l 6 8 10 -8 mol/l 10 -7 mol/l 7 7 10 -7 mol/l neutraal 10 -8 mol/l 8 6 10 -6 mol/l basisch 10 -9 mol/l 10 -10 mol/l 10 -11 mol/l 10 -12 mol/l 10 -13 mol/l 10 -14 mol/l

Zuurtegraad<br />

[H 3O + ] pH pOH [OH - ] oplossing<br />

1 mol/l 0 14 10 -14 mol/l zuur<br />

10 -1 mol/l 1 13 10 -13 mol/l<br />

10 -2 mol/l 2 12 10 -12 mol/l<br />

10 -3 mol/l 3 11 10 -11 mol/l<br />

10 -4 mol/l 4 10 10 -10 mol/l<br />

10 -5 mol/l 5 9 10 -9 mol/l<br />

10 -6 mol/l 6 8 10 -8 mol/l<br />

10 -7 mol/l 7 7 10 -7 mol/l neutraal<br />

10 -8 mol/l 8 6 10 -6 mol/l basisch<br />

10 -9 mol/l<br />

10 -10 mol/l<br />

10 -11 mol/l<br />

10 -12 mol/l<br />

10 -13 mol/l<br />

10 -14 mol/l

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