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6. Zuren en basen

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Waterconstante<br />

• H 2O + H 2O OH - + H 3O +<br />

K c = [OH - ] e.[H 3O + ] e /[H 2O] e²<br />

= 10 -7 mol/l x 10 -7 mol/l / (55,5 mol/l)²<br />

= 3,25.10 -18 (⇒ ev<strong>en</strong>wicht naar links)<br />

• [H 2O] e = 55,5 mol/l (cte)<br />

⇒ K w = [OH - ] e.[H 3O + ] e<br />

= 10 -7 mol/l x 10 -7 mol/l<br />

= 10 -14 (Waterconstante)<br />

• pK w = -log K w = 14 = pH + pOH

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