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6. Zuren en basen

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Neutralisatie NaOH + HCl<br />

• [NaOH] 0 = 0,01 mol/l ⇒ pH = 12<br />

n NaOH = 0,001 mol in 100 ml<br />

• Neutralisatie: NaOH + HCl NaCl + H 2O<br />

OH - + H 3O + 2 H 2O<br />

• + 9 ml [HCl]=0,1 mol/l n HCl=0,0009 mol<br />

⇒ n NaOH = 0,0001 mol in 109 ml<br />

⇒ [OH - ] = 0,00092 mol/l ⇒ pH = 10,92<br />

• + 9,9 ml [HCl]=0,1 mol/l ⇒ pH = 9,96<br />

• + 10 ml ⇒ volledige neutralisatie ⇒ pH = 7,00<br />

• + 20 ml ⇒ n H3O+=0,001 mol in 120 ml ⇒ pH = 2,08

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