6. Zuren en basen
6. Zuren en basen
6. Zuren en basen
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Ev<strong>en</strong>wicht HCl-oplossing<br />
• HCl + H 2O H 3O + + Cl -<br />
• Heel sterke ionisatie, ev<strong>en</strong>wicht naar rechts<br />
• Vb1: [HCl] 0 = 0,1 mol/l ([HCl] e = 10 -9 mol/l)<br />
⇒ [H 3O + ] e = 0,1 mol/l ⇒ pH = 1<br />
• K c = [H 3O + ] e.[Cl - ] e /[H 2O] e.[HCl] e<br />
met [H 2O] e = 55,5 mol/l (cte)<br />
• K Z = [H 3O + ] e.[Cl - ] e /[HCl] e (zuurconstante)<br />
= 10 -1 x 10 -1 / 10 -9 = 10 7 (ev<strong>en</strong>w. rechts)<br />
• Vb2: [HCl] 0 = 0,01 mol/l ⇒ pH = 2
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