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WSKT 212 PAC

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Oplossing:<br />

Met behulp van die standaardnotasie volg in ΔABC dat<br />

2<br />

a<br />

2 2<br />

= b + c −2bccos<br />

A<br />

2 2 2<br />

( )( )<br />

∴ a = 5 427, 091 + 5 365, 057 − 2 5 427, 091 5 365, 057 cos15°<br />

= 58 237 153, 336 −56<br />

249 053, 364<br />

∴ a = 1 988 099, 972<br />

= 1410<br />

Dus, die lengte van BC, die hoofspan, is 1 410 m.<br />

Voorbeeld 2<br />

Bepaal die hoek tussen die bene van die trapleër:<br />

Oplossing:<br />

Benoem die driehoek, indien moontlik volgens standaardnotasie:<br />

185

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