U. Iljins, I. Ziemelis The Optimization of Some Parameters of a Flat Plate Solar Collectorπkµ k =L. (13)Thus, the special functions of the problem (1-8) can be expressed in the form:πkxXk(x) = DkcosL. (14)The summarization of the range (9) of the problem (1–8) should be started from k=0, because, as it is seen, thespecial function (14) is not equal to zero, if k=0. In this case, µ=0 is also the particular value. Then it is purposefulto separate the member k=0 of the range (9) and to look for the solution of each layer in the form:∞I I II I IT(x,y) I = T0+ A + By+U (x,y) = T0+ A + By+∑Yk(y)⋅X k(x)k=1, (15)∞II II II II IIIIT II(x,y)= T0+ A + B (y−δ1) + U (x,y) = A + B (y−δ1) + ∑Yk(y−δ1) ⋅X k(x)k=1∞III IIIIIIIII IIIIIITIII(x,y)= T0+ A + B (y−δ1−δ2)+ U (x,y) = T0+ A + B (y−δ1−δ2)+ ∑Yk(y−δ1−δ2)⋅X k(x)k=1whereA I , A II , A III , U I , U II , U III – functions.Further, solutions (15) have to be inserted into boundary conditions (3–8). For example, inserting solution(15) into boundary condition (3) the following coherenceIIB Aλ = α(16)irand condition for the function U I I∂UIλi= αrU∂yy=0(17)y=0are obtained.To continue the insertion procedure into conditions (3–8), we acquire a system of 6 linear equations forobtaining values of coefficients A I , A II , A III , B I , B II , B III:II⎧λiB = αrA⎪IIIIII III⎪−λgB = α(A + B δ3)⎪ I I II⎪A+ B δ1= An⎨ II I 1⎪λB− λiB = ∑ qiL i=1⎪IIII II III⎪λB+ αg( A + B δ2− A ) = Q⎪IIIII II III⎪⎩− λgB = αg( A + B δ2− A )(18) 1and 6 boundary conditions for functions U I , U II , U III :1In order to get equation 4, first of all its both sides should be multiplied by the particular value at m=0 and then integratedfrom zero to L.70 LLU Raksti 12 (308), 2004; 67-75 1-18
U. Iljins, I. Ziemelis The Optimization of Some Parameters of a Flat Plate Solar CollectorI⎧ ∂UI⎪λi= αrU⎪ ∂yy=0y=0⎪III⎪ ∂U− λg= αU⎪ ∂yy=δ1+ δ 2 + δ 3⎪⎪IIIU = U⎪y=δ1y=δ1⎨III∂U∂U⎪λ− λi=⎪ ∂y∂yy=δ1y=δ1⎪II⎪ ∂UIIλ+ αg( U⎪ ∂yy=δ1y=δ1+ δ 2⎪⎪III∂UII⎪−λg+ αg( U⎪ ∂y⎩y=δ1+ δ 2IIIn∑i=1+ δ 2y=δ1+ δ 2 + δ 3q δ ( x − xi−Uy = δ1+ δ 2III−U)y=δ1+ δ 2IIIoi) = 0y=δ1+ δ 2)(19.1)(19.2)(19.3)(19.4)(19.5)(19.6)For further development of the solution, expressions (15) in turn have to be inserted into the boundaryconditions (19) (see the point where function U is expanded as Y k⋅X k). For instance, inserting the formula for U Iinto condition (19.1) the following is obtained:λ ( AI BI ) X ( x)( AI BIi∑ µk k − k k= αr ∑ k + k ) Xk( x). (20)kIn the formula (20), by regrouping all members to one side and then grouping them at the particular functionsX k(x), it is obtained that this equality is equal to zero then and only then, if coefficients are equal to zero at allX k(x). It means thatwhereλ µ ( AI I) ( AIBIk − B k = α k + k ). (21)i krFrom expression (21) the coherence between coefficients A I and k BI can be found:kBIk= AIkλiµk/ αr−1= Aλ µ / α + 1ikλiµk=λ µThen the function U I can be written in the form:ikr/ α/ αrk−1+ 1Ik⋅ϕIk(22)rϕ Ik. (23)I IIU = ∑ A k (exp( µ ky)+ ϕ k exp( −µ ky)) cos µ kx.(24)kInserting U III into equation (19.2) and making an analogous procedure as shown before, the function U III canbe obtained as following:IIIUIII III= ∑ B k ( ϕ k exp( µ k (y − δ1− δ2)) + exp( −µ k (y − δ1− δ2)))cosµk x . (25)kwhereLLU Raksti 12 (307), 2004; 67-75 1-1871
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