Apollonii Pergaei quae graece exstant cum ... - Wilbourhall.org

Apollonii Pergaei quae graece exstant cum ... - Wilbourhall.org Apollonii Pergaei quae graece exstant cum ... - Wilbourhall.org

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CONICORUM LIBER IV. 17 abscisas, ita partes intus abscisae diuiduntur, ita ut partes correspondentes ad idem punctum positae sint, recta per puncta diuisionis ducta cum sectione in duobus punctis concurret, et rectae a punctis concursus ad punctum extrinsecus positum ductae lineam contingent. sit enim AB aliqua linearum, quas diximus, et a puncto aliquo z/ perducantur AE^ /IZ lineam secantes altera in 0, ^, altera autem in Z.jH., sitque AE : ®J = EA\ A®, AZ : AH = ZK : KH. dico, rectam ab ^ ad iiT ductam iu utramque partem ^j^y cum sectione concurrere, et rectas a punctis concursus ad z/ ductas sectionem contingere. quoniam enim E^, Zz/ singulae in binis punctis sectionem secant, fieri potest, ut a z/ diametrus sectionis ducatur. quare etiam contingentes ^^ in utramque partem. ducantur contingentes AB, /iA, et ducta BA, si fieri potest, per A, K ne cadat, sed aut per alterutrum aut per neutrum. prius per A solum cadat rectamque ZH in /1 H = ZM\ MH-, M secet. itaque [III, 37] Z A \ quod absurdum est; nam supposuimus, esse ZA\AH=ZK\KH, sin BA per neutrum punctorum A, K cadit, in utraque ^E, AZ absurdum eueniet. Apollonius, ed. Heiberg. II. 2

CONICORUM LIBER IV. 17<br />

abscisas, ita partes intus abscisae diuiduntur, ita ut<br />

partes correspondentes ad idem punctum positae sint,<br />

recta<br />

per puncta diuisionis ducta <strong>cum</strong> sectione in duobus<br />

punctis concurret, et rectae a punctis concursus<br />

ad punctum extrinsecus positum ductae lineam contingent.<br />

sit enim AB aliqua linearum, quas diximus, et a<br />

puncto aliquo z/ perducantur AE^ /IZ lineam secantes<br />

altera in 0, ^, altera autem in Z.jH., sitque<br />

AE : ®J = EA\ A®, AZ : AH = ZK :<br />

KH.<br />

dico, rectam ab ^ ad iiT ductam iu utramque partem<br />

^j^y <strong>cum</strong> sectione concurrere,<br />

et rectas a punctis concursus<br />

ad z/ ductas sectionem<br />

contingere.<br />

quoniam enim E^,<br />

Zz/ singulae in binis<br />

punctis sectionem secant,<br />

fieri potest, ut a z/ diametrus<br />

sectionis ducatur.<br />

quare etiam contingentes<br />

^^ in utramque partem. ducantur<br />

contingentes AB, /iA, et ducta BA, si fieri<br />

potest, per A, K ne cadat, sed aut per alterutrum<br />

aut per neutrum.<br />

prius per A solum cadat rectamque ZH in<br />

/1 H = ZM\ MH-,<br />

M secet. itaque [III, 37] Z A \<br />

quod absurdum est;<br />

nam supposuimus, esse<br />

ZA\AH=ZK\KH,<br />

sin BA per neutrum punctorum A, K cadit, in<br />

utraque ^E, AZ absurdum eueniet.<br />

Apollonius, ed. Heiberg. II. 2

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