11.07.2015 Views

LA GEOMETRIA IN MESOPOTAMIA

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YBC 7302Che numeri?Che relazione fra loro?3diametrod=2rc=πd459area A=πr 2Come avremmo fatto noi:c=2π r9 = 3 x 3r=c/2πr= 3/2π=3/2·3,14=0,4777A=π(c/2π) 2 =c 2 /4π=9/4π=0,71619A= πr 2 A=π0,4777 2 =0,71619oppure45 = 9 x 5 [;45] = [9] x [;5]9 x 1/12 = 9/12 =3/4 = 45/60= 0,75

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