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Costanti di Ionizzazione Basica<br />
B (aq)<br />
+ H 2<br />
O (l)<br />
OH - (aq) + BH+ (aq)<br />
K C = [OH - ][HB + ]/[B][H 2 O]<br />
se [H 2 O] ca. costante:<br />
K B = K C [H 2 O] = [OH - ][HB + ]/[B] COSTANTE DI IONIZZAZIONE BASICA<br />
E.g. 1:<br />
CH 3<br />
NH 2(aq)<br />
+ H 2<br />
O (l)<br />
OH - (aq) + CH 3 NH 3 + (aq)<br />
K B = [CH 3 NH 3+ ][OH - ]/[CH 3 NH 2 ] = 3.6×10 -4 M<br />
pK B = - log(K B ) = 3.44
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