THÈSE Nicolas VASSET

THÈSE Nicolas VASSET THÈSE Nicolas VASSET

luth.obspm.fr
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20.07.2013 Views

h = h rr + h τ . h τ h η h µ {h ri } i=1,2,3 h rθ = ∂hη 1 − ∂θ sin θ h rϕ = 1 ∂h sin θ η ∂hµ + ∂ϕ ∂θ ; ∂h µ , ∂ϕ P = h θθ − h ϕϕ /2 P ≡ h θθ − h ϕϕ 2 = ∂2hW 1 ∂h − ∂θ2 tan θ W ∂θ h θϕ = ∂2hX 1 ∂h − ∂θ2 tan θ X ∂θ ∆θϕ (∆θϕ + 2) h W = ∂2P 3 ∂P + ∂θ2 tan θ ∂θ ∆θϕ (∆θϕ + 2) h X = ∂2 h θϕ 3 + ∂θ2 tan θ ∂h θϕ ∂θ 1 − sin2 θ 1 − sin2 θ − 1 sin 2 θ ∂2hW ∂ − 2 ∂ϕ2 ∂θ ∂2hX ∂ + 2 ∂ϕ2 ∂θ ∂2P 2 − 2P + ∂ϕ2 sin θ 1 ∂h sin θ X ∂ϕ 1 ∂h sin θ W ; ∂ϕ 1 − sin2 ∂ θ 2hθϕ ∂ϕ2 − 2hθϕ − 2 sin θ , θϕ ∂ ∂h hθϕ + ∂ϕ ∂θ tan θ ∂ ∂ϕ , ∂P P + . ∂θ tan θ h η h µ (ℓ = 0) h W h X ℓ = 0 ℓ = 1 h H h H r = ∂hrr 3hrr 1 + + ∂r r H η η ∂h 3hη = ∆θϕ + ∂r r H µ µ ∂h 3hµ = ∆θϕ + ∂r r r (∆θϕh η − h) , + 1 r (∆θϕ + 2) h W + + 1 r (∆θϕ + 2) h X h − hrr 2 , .

T R 3 T ij = ∇ i L j + ∇ j L i + h ij 0 , ∇jh ij 0 = 0 ∇jT ij = 0 ⇐⇒ L i = 0 T ij L h ij 0 A = ∂hX 0 ∂r B = ∂hW 0 ∂r C = ∂h0 ∂r hµ 0 − , r − 1 2r ∆θϕh W 0 − hη0 ∂hrr 0 − ∂r + h0 r r + h0 − hrr 0 4r 3hrr 0 − r − 2∆θϕ A = B = C = 0 ⇐⇒ h0 = 0, , W ∂h0 ∂r + hW 0 r , h (∆h) rr = ∆h rr − 6hrr 4 − r2 r2 ∆θϕh η + 2h r2 (∆h) η = ∆h η + 2 ∂h r η η 2hη 2 ∂h + − ∂r r2 r ∂r (∆h) µ = ∆h µ + 2 ∂h r µ ∂r (∆h) W = ∆h W + 2hW r (∆h) X = ∆h X + 2hX 3hη + r + (∆θϕ + 2) hW r 1 3 + h − 2r 2r hrr , µ 2hµ 2 ∂h 3hµ + − + r2 r ∂r r + (∆θϕ + 2) hX , r 2hη + 2 r 2 , 2hµ + r2 r T r(∆h) = ∆h T r(∆h) ∆h. 2 , H µ H Hη = 0 −hrr /r

T R 3 <br />

<br />

<br />

<br />

T ij = ∇ i L j + ∇ j L i + h ij<br />

0 ,<br />

∇jh ij<br />

0 = 0 ∇jT ij = 0 ⇐⇒ L i = 0 <br />

T ij <br />

L h ij<br />

0 <br />

<br />

<br />

A = ∂hX 0<br />

∂r<br />

B = ∂hW 0<br />

∂r<br />

C = ∂h0<br />

∂r<br />

<br />

hµ 0<br />

− , <br />

r<br />

− 1<br />

2r ∆θϕh W 0 − hη0<br />

∂hrr 0<br />

−<br />

∂r<br />

+ h0<br />

r<br />

r + h0 − hrr 0<br />

4r<br />

3hrr 0<br />

−<br />

r<br />

− 2∆θϕ<br />

A = B = C = 0 ⇐⇒ h0 = 0,<br />

, <br />

W ∂h0 ∂r + hW 0<br />

r<br />

<br />

, <br />

<br />

<br />

<br />

<br />

h <br />

(∆h) rr = ∆h rr − 6hrr 4<br />

−<br />

r2 r2 ∆θϕh η + 2h<br />

r2 (∆h) η = ∆h η + 2 ∂h<br />

r<br />

η<br />

η<br />

2hη 2 ∂h<br />

+ −<br />

∂r r2 r ∂r<br />

(∆h) µ = ∆h µ + 2 ∂h<br />

r<br />

µ<br />

∂r<br />

(∆h) W = ∆h W + 2hW<br />

r<br />

(∆h) X = ∆h X + 2hX<br />

3hη<br />

+<br />

r + (∆θϕ + 2) hW<br />

r<br />

1 3<br />

+ h −<br />

2r<br />

<br />

2r hrr<br />

<br />

,<br />

<br />

µ<br />

2hµ 2 ∂h 3hµ<br />

+ − +<br />

r2 r ∂r r + (∆θϕ + 2) hX<br />

<br />

, <br />

r<br />

2hη<br />

+ 2 r<br />

2 , <br />

2hµ<br />

+<br />

r2 r<br />

T r(∆h) = ∆h T r(∆h) ∆h. <br />

2 , <br />

<br />

H µ <br />

H Hη = 0 <br />

−hrr /r

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