THÈSE Nicolas VASSET
THÈSE Nicolas VASSET THÈSE Nicolas VASSET
from luth.obspm.fr
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20.07.2013
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ψ 2 α (b−N) = 1000 µ (b−N) = 1
ψ 2 α (b−N) = 1000 µ (b−N) = 1
- Page 114 and 115: ˜γij = ψ −4 γij; ψ = 1 (γ
- Page 116 and 117: h ij h ij D
- Page 118 and 119: h ij
- Page 120 and 121: A ∆A − ψ4 N 2 LβLβA = A
- Page 122 and 123: ∆h µ + 2 ∂h r µ ∂r ∆h η
- Page 124 and 125: h ij h ij
- Page 126 and 127: MHΩ JK a M
- Page 128 and 129: MH JH MADM
- Page 130 and 131: 1 − ɛA M2 M 3
- Page 132 and 133: ˜γ ij
- Page 134 and 135: h ij A ˜ B
- Page 136 and 137: H IJ A ˜ B
- Page 138 and 139: AHE = 8π(M 2 ADM + M 4 ADM − J
- Page 140 and 141: MHawking(S2) ≥ MHawking(S1) S2
- Page 142 and 143: ɛ P := A 16πM 2 ADM ɛ A := ≤ 1
- Page 144 and 145: R = r + M 2 − a2 + M, 4r R
- Page 146 and 147: H (1−ɛA) r
- Page 148 and 149: ɛA ɛP A JK λ
- Page 150 and 151: (1 − ɛA) NH = 0.5
- Page 152 and 153: ɛP A NH = 0.55
- Page 154 and 155: Σt St
- Page 156 and 157: (b − N) (b − N) = −Cθ
- Page 158 and 159: t0
- Page 160 and 161: S t = t0
- Page 162 and 163: αN = 1000 µN = 1
- Page 166 and 167: ψ 2 α (b−N) = 1000 µ (
- Page 168 and 169: ψ 2 α (b−N) = 1000 µ (
- Page 170 and 171: ψ 2 α (b−N) = 1000 µ (
- Page 172 and 173: ψ 2 α (b−N) = 1000 µ (
- Page 174 and 175: ψ 2 α (b−N) = 1000 µ (
- Page 176: ψ 2 α (b−N) = 1000 µ (
ψ 2 <br />
α (b−N) = 1000 µ (b−N) = 1
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