THÈSE Nicolas VASSET

THÈSE Nicolas VASSET THÈSE Nicolas VASSET

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20.07.2013 Views

S t = t0 t = t0 S θ (l) 0 (θ, ϕ) θ (l) ∞ = 0 1 ∂θ N (l) (t) ∂t = µθ∆θϕθ (l) (t) − αθθ (l) (t). ψ 4˜s i ˜ Diψ + ˜ Di˜s i + ψ −2 Kij˜s i ˜s j − ψ 2 K = θ (l) (t)ψ 2 , ψ ψ ψ ∂ψ ∂t = βi ˜ Diψ + ψ 6 ( ˜ Diβ i − NK), β i

V i (b − N) 1 ∂(b − N) = µ(b−N)∆θϕ(b − N) − α(b−N)(b − N), N ∂t b = N V a 1 ∂V N i ∂t = αV ( (2) ∆V i + (2) R i jV j ), V i b = 1 s i ˜ Diψ ∂ψ ∂t − V i ˜ Diψ ψ 6 ( ˜ Diβ i − NK) . N0(θ, ϕ) N∞ 1 N ∂N ∂t = µN∆θϕN − αN(N − N∞). N0(θ, ϕ) S t = t0

V i <br />

(b − N) <br />

<br />

1 ∂(b − N)<br />

= µ(b−N)∆θϕ(b − N) − α(b−N)(b − N), <br />

N ∂t<br />

b = N <br />

<br />

V a <br />

<br />

<br />

<br />

<br />

<br />

1 ∂V<br />

N<br />

i<br />

∂t = αV ( (2) ∆V i + (2) R i jV j ), <br />

<br />

V i <br />

<br />

<br />

<br />

<br />

b = 1<br />

s i ˜ Diψ<br />

∂ψ<br />

∂t − V i ˜ Diψ ψ<br />

6 ( ˜ Diβ i − NK)<br />

<br />

. <br />

<br />

<br />

<br />

<br />

N0(θ, ϕ) N∞ <br />

1<br />

N<br />

∂N<br />

∂t = µN∆θϕN − αN(N − N∞). <br />

<br />

N0(θ, ϕ) <br />

<br />

<br />

<br />

<br />

<br />

<br />

S t = t0

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