THÈSE Nicolas VASSET
THÈSE Nicolas VASSET THÈSE Nicolas VASSET
h ij A ˜ B h ij A ˜ B h ij H i = Dih ij , H i = 0 H i h ij H r = ∂hrr 3hrr 1 + + ∂r r H η η ∂h 3hη = ∆θϕ + ∂r r H µ µ ∂h 3hµ = ∆θϕ + ∂r r r (∆θϕh η − h) , + 1 r (∆θϕ + 2) h W + + 1 r (∆θϕ + 2) h X h − hrr 2 , . A ˜ B h ij ⎧ ⎪⎨ ∂X hµ − = A, ∂r r ⎪⎩ ∂h µ 3hµ 1 + + ∂r r r (∆θϕ + 2) h X = 0; ⎧ ˜B ⎪⎨ ⎪⎩ lm = B lm + Clm 2(l + 1) , ∂hrr 3hrr 1 + + ∂r r r (∆θϕh η − h) = 0, ∂hη 3hη 1 + + (∆θϕ + 2) h ∂r r r W h − hrr + = 0. 2 B C hij h R3 HIJ A ˜ B
h ij A ˜ B h h ij H IJ A ˜ B
- Page 84 and 85: = 2M r = 0
- Page 86 and 87: θ (ξ)
- Page 88 and 89: a 2 > M 2
- Page 90 and 91: ∂ µ ∂t ∂ µ µ
- Page 92 and 93: mi Mi N
- Page 94 and 95: X i ψ
- Page 96 and 97: Σ (
- Page 98 and 99: θ (l) µ = 1 16π ζ
- Page 100 and 101: (M, gµν) S 2 × R l µ
- Page 102 and 103: 2π µ ∂
- Page 104 and 105: St θ (l) = 0 θ (k) < 0.
- Page 106 and 107: ¯κ
- Page 108 and 109: (Σt, γij, Kij)
- Page 110 and 111: ψ
- Page 112 and 113: ψ
- Page 114 and 115: ˜γij = ψ −4 γij; ψ = 1 (γ
- Page 116 and 117: h ij h ij D
- Page 118 and 119: h ij
- Page 120 and 121: A ∆A − ψ4 N 2 LβLβA = A
- Page 122 and 123: ∆h µ + 2 ∂h r µ ∂r ∆h η
- Page 124 and 125: h ij h ij
- Page 126 and 127: MHΩ JK a M
- Page 128 and 129: MH JH MADM
- Page 130 and 131: 1 − ɛA M2 M 3
- Page 132 and 133: ˜γ ij
- Page 136 and 137: H IJ A ˜ B
- Page 138 and 139: AHE = 8π(M 2 ADM + M 4 ADM − J
- Page 140 and 141: MHawking(S2) ≥ MHawking(S1) S2
- Page 142 and 143: ɛ P := A 16πM 2 ADM ɛ A := ≤ 1
- Page 144 and 145: R = r + M 2 − a2 + M, 4r R
- Page 146 and 147: H (1−ɛA) r
- Page 148 and 149: ɛA ɛP A JK λ
- Page 150 and 151: (1 − ɛA) NH = 0.5
- Page 152 and 153: ɛP A NH = 0.55
- Page 154 and 155: Σt St
- Page 156 and 157: (b − N) (b − N) = −Cθ
- Page 158 and 159: t0
- Page 160 and 161: S t = t0
- Page 162 and 163: αN = 1000 µN = 1
- Page 164 and 165: ψ 2 α (b−N) = 1000 µ (
- Page 166 and 167: ψ 2 α (b−N) = 1000 µ (
- Page 168 and 169: ψ 2 α (b−N) = 1000 µ (
- Page 170 and 171: ψ 2 α (b−N) = 1000 µ (
- Page 172 and 173: ψ 2 α (b−N) = 1000 µ (
- Page 174 and 175: ψ 2 α (b−N) = 1000 µ (
- Page 176: ψ 2 α (b−N) = 1000 µ (
h ij <br />
A ˜ B<br />
<br />
<br />
h ij A ˜ B <br />
<br />
h ij <br />
H i = Dih ij , <br />
H i = 0 <br />
<br />
H i <br />
h ij <br />
H r = ∂hrr 3hrr 1<br />
+ +<br />
∂r r<br />
H η η ∂h 3hη<br />
= ∆θϕ +<br />
∂r r<br />
H µ µ ∂h 3hµ<br />
= ∆θϕ +<br />
∂r r<br />
r (∆θϕh η − h) , <br />
+ 1<br />
r<br />
<br />
(∆θϕ + 2) h W +<br />
+ 1<br />
r (∆θϕ + 2) h X<br />
h − hrr<br />
2<br />
<br />
, <br />
<br />
. <br />
A ˜ B <br />
<br />
h ij <br />
⎧<br />
⎪⎨<br />
∂X hµ<br />
− = A,<br />
∂r r<br />
⎪⎩ ∂h µ 3hµ 1<br />
+ +<br />
∂r r r (∆θϕ + 2) h X = 0;<br />
<br />
⎧<br />
˜B<br />
⎪⎨<br />
⎪⎩<br />
lm = B lm + Clm<br />
2(l + 1) ,<br />
∂hrr 3hrr 1<br />
+ +<br />
∂r r r (∆θϕh η − h) = 0,<br />
∂hη <br />
3hη 1<br />
+ + (∆θϕ + 2) h<br />
∂r r r<br />
W <br />
h − hrr<br />
+ = 0.<br />
2<br />
<br />
B C <br />
hij h <br />
<br />
<br />
<br />
<br />
<br />
R3 <br />
<br />
<br />
HIJ A ˜ B
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