THÈSE Nicolas VASSET
THÈSE Nicolas VASSET THÈSE Nicolas VASSET
h ij h ij Dih ij = 0, ˜γ ij (˜γ ij ) = (h ij + f ij ) = 1. Dih ij T h ij = D i W j + D j W i + h ij T , = 0 h ij T h ij T A ˜ B A ˜ B ∆h ij = S ij ∆A = AS, ˜∆ ˜ B = ˜ BS,
AS BS S ij ˜ ∆ ∆A − ψ4 N 2 LβLβA = AS(h ij , N, ψ, β, A ij ), ˜∆ ˜ B − ψ4 N 2 LβLβ ˜ B = ˜ BS(h ij , N, ψ, β, A ij ), LβA = βiDiA hij A ˜ B A ˜ B hij ˜ C ˜ C ˜ B
- Page 66 and 67: = R > 0 ∀(θ, ϕ) ∀t
- Page 68 and 69: dt R = 6, Nr = 17, Nθ = 17,
- Page 70 and 71: dt R = 6, Nr = 17, Nθ = 17,
- Page 72 and 73: A, A, ˜ B
- Page 74 and 75: p (M, ηµν) D + (p)
- Page 76 and 77: ∗ = r + 2M r 2M − 1 .
- Page 78 and 79: T = 0
- Page 80 and 81: (x, y, z, t) r(xdx + ydy) −
- Page 82 and 83: ∂ µ ∂t
- Page 84 and 85: = 2M r = 0
- Page 86 and 87: θ (ξ)
- Page 88 and 89: a 2 > M 2
- Page 90 and 91: ∂ µ ∂t ∂ µ µ
- Page 92 and 93: mi Mi N
- Page 94 and 95: X i ψ
- Page 96 and 97: Σ (
- Page 98 and 99: θ (l) µ = 1 16π ζ
- Page 100 and 101: (M, gµν) S 2 × R l µ
- Page 102 and 103: 2π µ ∂
- Page 104 and 105: St θ (l) = 0 θ (k) < 0.
- Page 106 and 107: ¯κ
- Page 108 and 109: (Σt, γij, Kij)
- Page 110 and 111: ψ
- Page 112 and 113: ψ
- Page 114 and 115: ˜γij = ψ −4 γij; ψ = 1 (γ
- Page 118 and 119: h ij
- Page 120 and 121: A ∆A − ψ4 N 2 LβLβA = A
- Page 122 and 123: ∆h µ + 2 ∂h r µ ∂r ∆h η
- Page 124 and 125: h ij h ij
- Page 126 and 127: MHΩ JK a M
- Page 128 and 129: MH JH MADM
- Page 130 and 131: 1 − ɛA M2 M 3
- Page 132 and 133: ˜γ ij
- Page 134 and 135: h ij A ˜ B
- Page 136 and 137: H IJ A ˜ B
- Page 138 and 139: AHE = 8π(M 2 ADM + M 4 ADM − J
- Page 140 and 141: MHawking(S2) ≥ MHawking(S1) S2
- Page 142 and 143: ɛ P := A 16πM 2 ADM ɛ A := ≤ 1
- Page 144 and 145: R = r + M 2 − a2 + M, 4r R
- Page 146 and 147: H (1−ɛA) r
- Page 148 and 149: ɛA ɛP A JK λ
- Page 150 and 151: (1 − ɛA) NH = 0.5
- Page 152 and 153: ɛP A NH = 0.55
- Page 154 and 155: Σt St
- Page 156 and 157: (b − N) (b − N) = −Cθ
- Page 158 and 159: t0
- Page 160 and 161: S t = t0
- Page 162 and 163: αN = 1000 µN = 1
- Page 164 and 165: ψ 2 α (b−N) = 1000 µ (
h ij <br />
<br />
h ij <br />
<br />
Dih ij = 0, <br />
˜γ ij <br />
<br />
(˜γ ij ) = (h ij + f ij ) = 1. <br />
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<br />
<br />
<br />
<br />
<br />
<br />
Dih ij<br />
T<br />
h ij = D i W j + D j W i + h ij<br />
T , <br />
= 0 <br />
h ij<br />
T <br />
h ij<br />
T <br />
A ˜ B <br />
<br />
A ˜ B <br />
<br />
∆h ij = S ij <br />
<br />
∆A = AS, <br />
˜∆ ˜ B = ˜ BS,
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