THÈSE Nicolas VASSET
THÈSE Nicolas VASSET THÈSE Nicolas VASSET
˜γij = ψ −4 γij; ψ = 1 (γ) 12 , (f) fij h ij ˜γ ij = f ij + h ij .  ij = ψ 10 (K ij − 1 3 Kγij ); Dk˜γ ki = Dkh ki = 0, ψ Nψ β i h ij ∆ψ = − 1 ∆(Nψ) = Nψ 8 ÂijÂijψ −7 + 1 7 8 ÂijÂijψ −8 + ˜ R 8 − hijDiDj(Nψ) 8 ψ ˜ R∗ − h ij DiDjψ, ∆β i + 1 3 Di Djβ j = 2ψ 6 A ij DjN − 12Nψ 6 A ij DjΦ − 2N∆ i klψ 6 A kl , − h kl DkDlβ i − 1 3 hikDkDlβ l , ∂2hij 2 N − ∂t2 ψ4 ∆hij ∂h − 2Lβ ij ∂t + LβLβh ij = S ij hij(N, ψ, β i , Âij , h ij ). S ij hij Âij = ψ−10Kij Âij  ij = ψ6 2N (Lβ) ij + ∂hij ∂t − Lβh ij − 2 3 Dkβ k h ij ,
L fij h ij γij Kij ( ∂ ∂t )i h ij ∆h ij − ψ4 N 2 LβLβh ij = S ij 2 (h ij , N, ψ, β, A ij ). γij ˜
- Page 64 and 65: A h µ h X ˜
- Page 66 and 67: = R > 0 ∀(θ, ϕ) ∀t
- Page 68 and 69: dt R = 6, Nr = 17, Nθ = 17,
- Page 70 and 71: dt R = 6, Nr = 17, Nθ = 17,
- Page 72 and 73: A, A, ˜ B
- Page 74 and 75: p (M, ηµν) D + (p)
- Page 76 and 77: ∗ = r + 2M r 2M − 1 .
- Page 78 and 79: T = 0
- Page 80 and 81: (x, y, z, t) r(xdx + ydy) −
- Page 82 and 83: ∂ µ ∂t
- Page 84 and 85: = 2M r = 0
- Page 86 and 87: θ (ξ)
- Page 88 and 89: a 2 > M 2
- Page 90 and 91: ∂ µ ∂t ∂ µ µ
- Page 92 and 93: mi Mi N
- Page 94 and 95: X i ψ
- Page 96 and 97: Σ (
- Page 98 and 99: θ (l) µ = 1 16π ζ
- Page 100 and 101: (M, gµν) S 2 × R l µ
- Page 102 and 103: 2π µ ∂
- Page 104 and 105: St θ (l) = 0 θ (k) < 0.
- Page 106 and 107: ¯κ
- Page 108 and 109: (Σt, γij, Kij)
- Page 110 and 111: ψ
- Page 112 and 113: ψ
- Page 116 and 117: h ij h ij D
- Page 118 and 119: h ij
- Page 120 and 121: A ∆A − ψ4 N 2 LβLβA = A
- Page 122 and 123: ∆h µ + 2 ∂h r µ ∂r ∆h η
- Page 124 and 125: h ij h ij
- Page 126 and 127: MHΩ JK a M
- Page 128 and 129: MH JH MADM
- Page 130 and 131: 1 − ɛA M2 M 3
- Page 132 and 133: ˜γ ij
- Page 134 and 135: h ij A ˜ B
- Page 136 and 137: H IJ A ˜ B
- Page 138 and 139: AHE = 8π(M 2 ADM + M 4 ADM − J
- Page 140 and 141: MHawking(S2) ≥ MHawking(S1) S2
- Page 142 and 143: ɛ P := A 16πM 2 ADM ɛ A := ≤ 1
- Page 144 and 145: R = r + M 2 − a2 + M, 4r R
- Page 146 and 147: H (1−ɛA) r
- Page 148 and 149: ɛA ɛP A JK λ
- Page 150 and 151: (1 − ɛA) NH = 0.5
- Page 152 and 153: ɛP A NH = 0.55
- Page 154 and 155: Σt St
- Page 156 and 157: (b − N) (b − N) = −Cθ
- Page 158 and 159: t0
- Page 160 and 161: S t = t0
- Page 162 and 163: αN = 1000 µN = 1
˜γij = ψ −4 γij; ψ =<br />
1<br />
(γ) 12<br />
, <br />
(f)<br />
fij <br />
<br />
h ij <br />
<br />
˜γ ij = f ij + h ij . <br />
<br />
 ij = ψ 10 (K ij − 1<br />
3 Kγij ); <br />
<br />
<br />
Dk˜γ ki = Dkh ki = 0, <br />
<br />
<br />
<br />
ψ Nψ β i h ij <br />
<br />
∆ψ = − 1<br />
∆(Nψ) = Nψ<br />
8 ÂijÂijψ −7 + 1<br />
<br />
7<br />
8 ÂijÂijψ −8 + ˜ R<br />
8 − hijDiDj(Nψ) 8 ψ ˜ R∗ − h ij DiDjψ, <br />
<br />
∆β i + 1<br />
3 Di Djβ j = 2ψ 6 A ij DjN − 12Nψ 6 A ij DjΦ − 2N∆ i klψ 6 A kl<br />
, <br />
− h kl DkDlβ i − 1<br />
3 hikDkDlβ l , <br />
∂2hij 2 N<br />
−<br />
∂t2 ψ4 ∆hij ∂h<br />
− 2Lβ<br />
ij<br />
∂t + LβLβh ij = S ij<br />
hij(N, ψ, β i , Âij , h ij ). <br />
S ij<br />
hij <br />
Âij =<br />
ψ−10Kij <br />
<br />
Âij <br />
<br />
 ij = ψ6<br />
2N<br />
<br />
(Lβ) ij + ∂hij<br />
∂t − Lβh ij − 2<br />
3 Dkβ k h ij<br />
<br />
,