PORTAL TIGA SENDI - burhan
PORTAL TIGA SENDI - burhan
PORTAL TIGA SENDI - burhan
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C � Bidang momen<br />
BMD<br />
� Batang AC ditinjau dari titik A<br />
M A = 0<br />
M F = A H 1 = 3,75 tm (+)<br />
M E = A H . 3 – 3 . 2 = 3,75 . 3 – 6 = 5,25 tm (+)<br />
M C = A H . 4 – 3 . 3 – 1 . 1 = 3,75 . 4 – 9 – 1 = 5 tm (+)<br />
Momen ditengah-tengah batang AC � x = 2 m<br />
M X=2 = A H . 2 – 3 . 1 = 3,75 . 2 – 3 = 4,5 tm<br />
� Batang CD ditinjau dari C<br />
M X = A H . 4 – A V . x – 1 . 1 – 3 . 3 = 3,75 . 4 – 2,5x - 10<br />
Pada x = 0, berarti di titik C<br />
M x=0 = M C = 15 – 0 – 10 = 5 tm (+) � sama dgn hitungan dari A<br />
M x=2 = M S = 15 – 5 – 10 = 0 tm ( Momen di S selalu nol …ok)<br />
M x=4 = M D = 15 – 10 – 10 = - 5 tm<br />
M D dari batang BD = B H . 4 = - 1,25 . 4 = - 5 tm
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