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MODUL-MATEMATIKA-EKONOMI-2

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Laboratorium Manajemen DasarJawab :Cara 1Pd = Ps P = 55 – 4(10)55 - 4Q = 5 + Q Pe = 15- Q - 4Q = 5 – 55- 5Q = - 50Qe = 10Cs = ∫ f(Q)dQ − Qe . Pe= ∫ [55 – 4Q] dQ – 10 . 15= [55Q – 2Q 2 ] – 150= [55(10) – 2(10) 2 ] – [55(0) – 2(0) 2 ] – 150= 350 – 0 – 150= 200Analisis:Jadi surplus yang diperoleh konsumen tersebut sebesar Rp 200 karenakonsumen dapat membeli dengan harga Rp 15 padahal konsumen sanggupmembayar lebih tinggi dari harga keseimbangan pasar yang bernilai Rp 15.Grafik Surplus Konsumen Soal 1Matematika Ekonomi 2 60 Litbang ATA 13/14

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