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Mathematics Modern Q&A - Trial Paper Collection

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SULIT 1449/119 3p 2 – 19p + 6 =A (3p – 1)(p – 6)B (3p – 6)(p + 1)C (3p – 6)(p – 1)D (3p + 1)(p – 6)20Express2 2a 1 3aas a single fraction in its simplest form.Ungkapkan2 2a 1 3asebagai satu pecahan tunggal dalam bentuk termudah.ABCD4a13a(a 1)4a13a(a 1)2(2a1)3a(a 1)23a21Given thatDiberi bahawaABCDk3k 2k2 3k3k 2k2 3kk2lk = , express l in terms of k.3 l + 12lk = , ungkapkan l dalam sebutan k.3 l + 11449/1 2011 Hak Cipta SBP 18[Lihat sebelahSULIT

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