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Analisis Rangkaian Listrik Jilid-2 - Ee-cafe.org

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CONTOH-5.2: Carilah fungsi alih rangkaian-rangkaian berikut.<br />

+<br />

V in (s)<br />

−<br />

Solusi :<br />

R<br />

a).<br />

1<br />

Cs<br />

Fungsi Jaringan<br />

Kaidah pembagi tegangan untuk rangkaian a) dan kaidah pembagi<br />

arus untuk rangkaian b) akan memberikan :<br />

Vo<br />

( s)<br />

1/ Cs 1<br />

a). TV<br />

( s)<br />

= = = ;<br />

V ( s)<br />

R + 1/ Cs RCs + 1<br />

I<br />

b). TI<br />

( s)<br />

=<br />

I<br />

in<br />

o<br />

in<br />

+<br />

V o (s)<br />

−<br />

I in (s)<br />

1<br />

Cs<br />

b).<br />

R<br />

( s)<br />

1/ R 1<br />

= =<br />

( s)<br />

1/ R + sC 1 + sRC<br />

I o (s)<br />

CONTOH-5.3: Tentukan impedansi<br />

masukan dan fungsi alih rangkaian<br />

di samping ini.<br />

Solusi :<br />

+<br />

v in<br />

−<br />

L<br />

R 1<br />

R<br />

C<br />

2<br />

+<br />

v o<br />

−<br />

Transformasi rangkaian ke kawasan<br />

s memberikan<br />

+<br />

V in (s)<br />

−<br />

Ls<br />

R 1<br />

R<br />

1/Cs<br />

2<br />

+<br />

V o (s)<br />

−<br />

( R + 1/ Cs) || ( Ls + R )<br />

Z in<br />

Vo<br />

( s)<br />

R2<br />

TV<br />

( s)<br />

= = V in ( s)<br />

Ls + R2<br />

= 1<br />

2<br />

( R1<br />

+ 1/ Cs)(<br />

Ls + R )<br />

=<br />

2<br />

R1<br />

+ 1/ Cs + R2<br />

+ Ls<br />

( R1Cs<br />

+ 1)( Ls + R2<br />

)<br />

=<br />

2<br />

LCs + ( R1<br />

+ R2)<br />

Cs + 1<br />

109

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