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Analisis Rangkaian Listrik Jilid-2 - Ee-cafe.org

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4.8.1. Metoda Unit Output<br />

<strong>Analisis</strong> <strong>Rangkaian</strong> Menggunakan Transformasi Laplace<br />

CONTOH-4.4: Dengan menggunakan metoda unit output, carilah<br />

V 2 (s) pada rangkaian impedansi di bawah ini.<br />

I L (s)<br />

sL<br />

I 1 (s) I R (s)<br />

Solusi :<br />

Misalkan : V2(<br />

s)<br />

= 1<br />

→VC<br />

( s)<br />

= V2(<br />

s)<br />

= 1<br />

→ IL(<br />

s)<br />

= IC<br />

( s)<br />

= sC<br />

R<br />

I C (s)<br />

1/sC<br />

+<br />

V 2 (s)<br />

−<br />

1<br />

→ IC<br />

( s)<br />

= = sC<br />

1/ sC<br />

2<br />

→ VL(<br />

s)<br />

= sL × sC = LCs<br />

2<br />

2<br />

LCs + 1<br />

→VR(<br />

s)<br />

= VL(<br />

s)<br />

+ VC<br />

( s)<br />

= LCs + 1 → IR(<br />

s)<br />

=<br />

R<br />

2<br />

2<br />

*<br />

LCs + 1 LCs + RCs + 1<br />

⇒ I1<br />

( s)<br />

= IR(<br />

s)<br />

+ I L(<br />

s)<br />

= + sC =<br />

R<br />

R<br />

1 R<br />

⇒ Ks<br />

= =<br />

*<br />

2<br />

I1<br />

( s)<br />

LCs + RCs + 1<br />

R<br />

⇒V2(<br />

s)<br />

= KsI1(<br />

s)<br />

=<br />

I1(<br />

s)<br />

2<br />

LCs + RCs + 1<br />

4.8.2. Metoda Superposisi<br />

CONTOH-4.5: Dengan menggunakan metoda superposisi, carilah tegangan<br />

induktor v o (t)<br />

pada rangkaian berikut<br />

ini.<br />

Solusi :<br />

Au(t)<br />

<strong>Rangkaian</strong> kita transformasikan<br />

ke kawasan s menjadi<br />

+<br />

−<br />

R<br />

L<br />

+<br />

v o<br />

−<br />

R<br />

Bsinβt<br />

94 Sudaryatno Sudirham, <strong>Analisis</strong> <strong>Rangkaian</strong> <strong>Listrik</strong> (2)

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