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248<br />

7. Kadar O pada FeO =<br />

Ar<br />

O<br />

× 100%<br />

M FeO<br />

= 16 gram/mol × 100%<br />

72 gram/mol<br />

= 22,2%<br />

Kadar O pada Fe O 2 3 =<br />

2 × Ar<br />

O<br />

× 100%<br />

r<br />

M<br />

r<br />

Fe O<br />

2 3<br />

=<br />

32 gram mol<br />

× 100%<br />

160 gram mol<br />

=<br />

9. a. Massa CaS = 45 gram<br />

20%<br />

b. Massa pereaksi yang sisa = 10 gram kalsium<br />

11. x = 2, jadi rumus senyawa CaSO .2H O 4 2<br />

13. a. Massa CH4 b. Massa N O 2<br />

c. Massa C H 3 8<br />

d. Massa H S 2<br />

e. Massa H O 2<br />

=<br />

=<br />

=<br />

=<br />

=<br />

64 gram<br />

11 gram<br />

88 gram<br />

3,4 gram<br />

5,4 gram<br />

15. 2 C 2 H 6 + 7 O 2 ⎯⎯→ 4 CO 2 + 6 H 2 O<br />

17. Massa CH4 = 10 gram<br />

19. Massa KClO3 = 2,45 gram<br />

Latihan Ulangan Umum Semester 1<br />

Kimia X SMA<br />

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1. E 21. E<br />

3. C 23. B<br />

5. A 25. A<br />

7. C 27. C<br />

9. E 29. B<br />

11. C 31. C<br />

13. D 33. B<br />

15. D 35. D<br />

17. B 37. C<br />

19. D 39. B<br />

Bab 4 Larutan Elektrolit-Nonelektrolit dan Konsep Redoks<br />

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I. Pilihan Ganda<br />

1. E 11. D<br />

3. A 13. B<br />

5. C 15. E<br />

7. A 17. C<br />

9. C 19. E

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