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Ruas Kanan

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Kimia X SMA 247<br />

15. Perbedaan senyawa polar dengan nonpolar sebagai berikut.<br />

Polar:<br />

- Keelektronegatifan berbeda.<br />

- Tidak simetris karena lebih tertarik ke atom dengan daya elektron lebih besar.<br />

Contoh: HCl, HF, dan HBr.<br />

Nonpolar:<br />

- Keelektronegatifan sama.<br />

- Simetris terhadap kedua atom.<br />

- Muatan elektron tersebar homogen.<br />

Contoh: H , Cl , dan O .<br />

2 2 2<br />

Bab 3 Stoikiometri<br />

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I. Pilihan Ganda<br />

1. D 21. D 49. B<br />

3. D 23. E 51. E<br />

5. A 25. D 53. B<br />

7. B 27. A 55. D<br />

9. D 29. B 57. D<br />

11. D 31. D 59. B<br />

13. C 33. C 61. C<br />

15. B 35. E 63. D<br />

17. E 37. C 65. D<br />

19. A 39. D 67. C<br />

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II. Uraian<br />

1. a. Zn(s) + 2 HCl(aq) ⎯⎯→ ZnCl (aq) + H (g)<br />

2 2<br />

b. Ca(OH) (aq) + 2 HCl(aq) ⎯⎯→ CaCl (aq) + 2 H O(l)<br />

2 2 2<br />

c. 3 I (s) + 6 NaOH(aq) ⎯⎯→ 5 NaI(aq) + NaIO (aq) + 3 H O(l)<br />

2 3 2<br />

d. Fe O (s) + HBr(aq) ⎯⎯→ FeBr (aq) + H O(l)<br />

2 3 3 2<br />

e. Pb(NO ) (aq) + NaCl(aq) ⎯⎯→ PbCl (s) + NaNO (aq)<br />

3 2 2 3<br />

3. 100 N O ⎯⎯→ 100 NO + 50 O x y 2<br />

2 N O ⎯⎯→ 2 NO + O x y 2<br />

⎯⎯→ CO 2 + 2 H 2 O<br />

5. CH + 4<br />

8 – x<br />

2 O2 2(8 – x)<br />

C H + 3 8<br />

x<br />

5 O2 5x<br />

Volume O : 2<br />

2(8 – x) + 5x = 25<br />

16 – 2x + 5x = 25<br />

3x = 9<br />

x = 3<br />

x = 3 liter<br />

Volume C H = 3 8<br />

Volume CH = 4<br />

x =<br />

8 – x<br />

3 liter<br />

= 5 liter<br />

⎯⎯→ 3 CO 2 + 4 H 2 O

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