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Kelas IX_SMP_IPA_Sukis Wariyono.pdf

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Jika kedua ruas dibagi dengan V, diperoleh rumus hambatan<br />

pengganti paralel:<br />

1 1 1 1<br />

= + +<br />

R R R<br />

R P<br />

1. Berdasarkan gambar berikut,<br />

tentukan:<br />

I 1<br />

a. hambatan pengganti paralel,<br />

b. arus listrik yang mengalir<br />

dalam rangkaian,<br />

c. arus listrik yang mengalir pada<br />

setiap hambatan R 1 , R 2 , dan<br />

R 3 .<br />

146 Mari BIAS 3<br />

1<br />

2<br />

3<br />

Jika ada n buah hambatan masing-masing R 1 , R 2 , R 3 , ... R n ,<br />

hambatan pengganti paralel dari n buah hambatan secara umum<br />

dirumuskan:<br />

1<br />

R<br />

P<br />

1 1 1 1<br />

= + + + ... +<br />

R R R R<br />

1<br />

2<br />

3<br />

R 1 = 60 Ω<br />

n<br />

Penyelesaian:<br />

Diketahui: R1 = 60 Ω R3 = 40 Ω<br />

R2 = 120 Ω V = 6 V<br />

I2 R = 120 Ω<br />

2 Ditanya: a. R = ... ?<br />

P<br />

b. I = ... ?<br />

I3 R = 40 Ω<br />

3<br />

Jawab:<br />

c. I = ... ?, I = ... ?, I = ... ?<br />

1 2 3<br />

I V = 6 V<br />

a.<br />

1<br />

RP<br />

1<br />

=<br />

R1<br />

1<br />

+<br />

R2<br />

1<br />

+<br />

R3<br />

b.<br />

V<br />

I =<br />

R P<br />

1 1 1<br />

= + +<br />

60 120 40<br />

6<br />

=<br />

20<br />

2 + 1 + 3 6<br />

= =<br />

120 120<br />

= 0,3 Ω<br />

c. I 1 =<br />

120<br />

R = = 20 P Ω<br />

6<br />

V<br />

R1<br />

6<br />

=<br />

60<br />

I 3<br />

=<br />

V<br />

R3<br />

6<br />

=<br />

40<br />

= 0,1 A = 0,15 A<br />

V<br />

I = 2 R2<br />

6<br />

= = 0,05 A<br />

120

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