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Numerikus sorok - Index of

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✎☞<br />

✍✌ T a n , b n , c n , d n > 0<br />

⎧<br />

1. a n + b n ∼ c n + d n<br />

}<br />

a n ∼ c n<br />

b n ∼ d n<br />

=⇒<br />

⎪⎨<br />

⎪⎩<br />

2. a n b n ∼ c n d n<br />

3.<br />

4.<br />

1<br />

∼ 1 a n c n<br />

b n<br />

∼ d n<br />

a n c n<br />

Megint nincs különbség!<br />

✎☞<br />

B ✍✌<br />

a n ∼ c n : a n<br />

→ 1 =⇒ 0 < 1 − ε < a n<br />

< 1 + ε, n > N 1<br />

c n c n<br />

b n ∼ d n :<br />

Legyen n > max{N 1 , N 2 } = N<br />

b n<br />

d n<br />

→ 1 =⇒ 0 < 1 − ε < b n<br />

d n<br />

< 1 + ε, n > N 2<br />

1. 1 − ε = (1 − ε)c n + (1 − ε)d n<br />

c n + d n<br />

< a n + b n<br />

c n + d n<br />

< (1 + ε)c n + (1 + ε)d n<br />

c n + d n<br />

= 1 + ε ,<br />

ha n > N<br />

2. ¬B<br />

3.<br />

1<br />

a n<br />

1<br />

c n<br />

= c n<br />

a n<br />

= 1 a n<br />

cn<br />

→ 1<br />

4. Az előző kettőből következik: a n ∼ c n =⇒ 1 a n<br />

∼ 1 c n<br />

; másrészt b n ∼ d n<br />

=⇒ b n<br />

a n<br />

∼ d n<br />

c n<br />

✓✏<br />

Pl.<br />

✒✑a n = 3√ 2n 2 + n + 1 − 3√ 2n 2 − 3n − 7 =<br />

2n 2 + n + 1 − (2n 2 − 3n − 7)<br />

= ( √ 3<br />

2n2 + n + 1 ) 2 √ +<br />

3<br />

2n 2 + n + 1 3√ 2n 2 − 3n − 7 + ( √ 3<br />

2n 2 − 3n − 7 ) 2 ∼<br />

∼<br />

(<br />

)<br />

3√ 2 2 (<br />

2 n 3 +<br />

4n<br />

3√<br />

2 n<br />

2<br />

3<br />

) 2<br />

+<br />

(<br />

)<br />

3√ 2 2<br />

=<br />

2 n 3<br />

4n<br />

3√<br />

4 · 3 n<br />

4<br />

3<br />

=<br />

4<br />

3 3√ 4 3√ n<br />

=⇒ a n → 0<br />

✓✏<br />

Pl.<br />

✒✑a n =<br />

arctg √ n<br />

3√<br />

2n2 + n + 1 − 3√ 2n 2 − 3n − 7 ∼<br />

π<br />

2<br />

4<br />

3 3√ 4 3√ n<br />

=konst· 3√ n → ∞<br />

c○ Kónya I. – Fritz Jné – Győri S. 34 v1.4

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