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Numerikus sorok - Index of

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6. Műveletek konvergens <strong>sorok</strong>kal<br />

✎☞ ∞∑<br />

∞∑<br />

✍✌ T Ha a k = S a és b k = S b , S a , S b ∈ R<br />

k=1<br />

k=1<br />

∑<br />

=⇒ ∞ ∞∑<br />

(a k + b k ) = S a + S b és (c · a k ) = c · S a .<br />

k=1<br />

k=1<br />

✎☞<br />

B ✍✌<br />

S a = lim<br />

n∑<br />

n → ∞ sa n = lim a k<br />

n → ∞<br />

k=1<br />

n∑<br />

S b = lim<br />

n → ∞ sb n = lim b k<br />

n → ∞<br />

k=1<br />

(<br />

n∑<br />

n<br />

)<br />

∑ ∑<br />

S a+b = lim<br />

n → ∞ sa+b n = lim (a k + b k ) = lim a k +<br />

n b k =<br />

n → ∞<br />

k=1<br />

n → ∞<br />

( k=1 k=1<br />

n<br />

) (<br />

∑<br />

n<br />

)<br />

∑<br />

lim a k + lim b k = S a + S b<br />

n → ∞<br />

k=1<br />

n → ∞<br />

k=1<br />

Másrészt<br />

S c a = lim<br />

n → ∞ sc n<br />

a = lim<br />

n → ∞<br />

n∑<br />

k=1<br />

(c a k ) = c lim<br />

n → ∞<br />

n∑<br />

k=1<br />

a k = c S a<br />

6.1. Végtelen <strong>sorok</strong> természetes szorzata<br />

a 1 + a 2 + a 3 + a 4 + · · · + a k + · · ·<br />

b 1 b 1 a 1 + b 1 a 2 + b 1 a 3 + b 1 a 4 + · · · + b 1 a k + · · ·<br />

+<br />

b 2 b 2 a 1 + b 2 a 2 + b 2 a 3 + b 2 a 4 + · · · + b 2 a k + · · ·<br />

+<br />

b 3 b 3 a 1 + b 3 a 2 + b 3 a 3 + b 3 a 4 + · · · + b 3 a k + · · ·<br />

+<br />

b 4 b 4 a 1 + b 4 a 2 + b 4 a 3 + b 4 a 4 + · · · + b 4 a k + · · ·<br />

+. .<br />

+<br />

b k b k a 1 + b k a 2 + b k a 3 + b k a 4 + · · · + b k a k + · · ·<br />

+. .<br />

A természetes szorzat elemei:<br />

c○ Kónya I. – Fritz Jné – Győri S. 25 v1.4

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