13.07.2015 Views

ENERGIE E (KeV)

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Contraste dans l’image radiantePour un faisceau parallèle monoénergétiqueEn un point 1: X 1 = X 0 e –µ 1 x 1En un point 2: X 2 = X 0 e –µ 2 x 2Si x1 = x2 = x, alors le contraste C entre les points1 et 2 del’image radiante est:C = Ln (X 1 / X 2 ) = (µ 2 - µ 1 ).xC décroît lorsque l’énergie des RX augmente (lorsque Uaugmente), car alors (µ 2 - µ 1 ) diminue.

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