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291<br />

1.1.3 N ((N 1 f) a) 1.1.2, ∑ * 1 - e<br />

1.1.4 (f a) 1.1.3, th L c<br />

1.2. x, (f x) 1.1.1 - 1.1.4, N - i<br />

1.3. ∏ 1 f 1.2, ∏ 1 - i<br />

1.4. (N (∏ 1 f)) 1, réitération<br />

2. *<br />

(N (N ∑ 1 (N1 f))) 1.1 - 1.4, N - i<br />

3. *<br />

∑ 1 (N1 f) 2, N - e / N<br />

La démonstration de (22)<br />

*<br />

∑ (N f)<br />

1<br />

(N( ∏ f)) N∏ 1 - i (22)<br />

1<br />

1. ∑ 1<br />

* (N1 f) hypothèse<br />

1.1. ∏ 1 f hypothèse<br />

1.2. x, (f x) 1.1, ∏ 1 - e<br />

1.3 ∑ 1<br />

*<br />

(N 1 f) 1, réitération<br />

1.4 a, ((N 1 f) a) 1.3, ∑ * 1 - e<br />

1.5 a, (f a) 1.2, ∀ -e<br />

2. (N (∏ 1 f)) 1.1- 1.4,1.5, N - i<br />

La démonstration de (25):<br />

*<br />

(N( ∏ f))<br />

1<br />

∑ * 1<br />

((N 1<br />

f)∨ (Atyp 2<br />

f) N∏ * 1 - e (25)<br />

1. (N (∏ 1<br />

*<br />

f)) hypothèse<br />

2. (N (Typ 2 f) x) *<br />

1, ∏ 1 - e<br />

3. a, (N (Typ 2 f) a) 2, N ∀ - e<br />

4. *<br />

∑ 1 (N 1 (Typ 2 f)) 3, ∑ * 1 - i<br />

5. *<br />

∑ 1 ((N1 f) ∨ (Atyp 2 f)) 4, th.2<br />

La démonstration de (24):<br />

∑ 1<br />

(N 1<br />

f)<br />

*<br />

(N ( ∏ f)) N∏ * 1 - i (24)<br />

1

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