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ARIASJOHN_PORTAFOLIO

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E = 220v<br />

I =?<br />

I = E R<br />

I = 220v<br />

500w<br />

I = 2.27A<br />

= 220v<br />

2.27A<br />

R = 96.91Ω<br />

R = E²<br />

P = 96.8Ω<br />

R = P I² = 97.03<br />

Calor que produce<br />

Q = 0.24 w<br />

W = p ∗ t<br />

= 0.24(120.000) = 500w ∗ 240h<br />

= 28.800cal. W = 120.000,00<br />

Energía consumida<br />

W = 120. 000<br />

1000 = 120kmh<br />

Trifa dignidad 0.4ctvs<br />

= 120 ∗ 0. 095 + 0. 02 Normal 9.33 ctvs.<br />

Valor ha pagar = 120 ∗ 0. 113 = 13. 5$<br />

Comercial normal +2ctvs<br />

Calcular la potencia eléctrica y consumo de energía de un motor por el watt pasa una<br />

intensidad de 4 amperios y tiene una resistencia de 100Ω, si el motor ha estado<br />

funcionando por 4 horas los 5 días de la semana durante todo el mes.<br />

¿Aplicar el upiur?<br />

P =? E = I. R P = 1600w Q = 0.24w<br />

R = 100 E = (4a)(100Ω) W = P. T<br />

t = 4h E = 400v W = (1600w)(4 ∗ 22)<br />

l = 4A mes p = I. E W = 140.800wh<br />

l = p t<br />

P = (4A)(400V)<br />

W=<br />

400.800 wh<br />

1000<br />

W =<br />

140.8kwh<br />

Calor Tarifa comercial =0.113$

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