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lo cual significa que<br />
- t;<br />
00 (_1)k(2v+2k)X2v+2k-l<br />
2 v + 2k k! r(v + k + 1)<br />
00 (-1)k2(v + k)X2v+2k-l<br />
{;2 v + 2k k! (v+k)r(v+k)<br />
XV 00 (_1)k(x/2)(v-l)+2k<br />
- t; k! r [(v - 1) + k + 1]<br />
d~ [XVJv(x)] = XVJv-1 (x)<br />
(14)<br />
Análogamente, se <strong>de</strong>muestra que<br />
~ [x-v Jv(x)] = -x-v Jv+1(x)<br />
(15)<br />
Derivando el lado izquierdo <strong>de</strong> (14) como un producto, se t.iene<br />
ele don<strong>de</strong>, al multiplicar por x-v, resulta<br />
De la misma manera, <strong>de</strong>sarrollando la <strong>de</strong>rivada en (15) y multiplicando<br />
luego por z", se obtiene<br />
(16)<br />
_!:JV(x) + J~(x) = -Jv+ 1 (x)<br />
x<br />
Sumando y rest.ando las fórmulas (16) y (17), resultan<br />
(17)<br />
(18)<br />
y<br />
(19)<br />
respectivamente.<br />
5
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