Pensar en C++ (Volumen 1) - Grupo ARCO

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✐ ✐ ✐ “Volumen1” — 2012/1/12 — 13:52 — page 386 — #424 ✐ Capítulo 13. Creación dinámica de objetos memset(st, 0, (quantity + increase) * psz); memcpy(st, storage, quantity * psz); quantity += increase; delete []storage; // Old storage storage = st; // Point to new memory } ///:~ La función add() es, en efecto, la misma que antes si exceptuamos el hecho de que lo que se almacena ahora es un puntero a un objeto en lugar de una copia del objeto. El código de inflate() ha sido modificado para gestionar la asignación de memoria para un vector de void*, a diferencia del diseño previo, que sólo trataba con bytes. Aquí, en lugar de usar el método de copia por el índice del vector, se pone primero a cero el vector usando la función memset() de la biblioteca estándar de C, aunque esto no sea estrictamente necesario ya que, presumiblemente, PStash manipulará la memoria de forma adecuada, pero a veces no es muy costoso añadir un poco más de seguridad. A continuación, se copian al nuevo vector usando m- emcpy() los datos existentes en el antiguo. Con frecuencia verá que las funciones memcpy() y memset() han sido optimizadas en cuanto al tiempo de proceso, de modo que pueden ser más rápidas que los bucles anteriormente vistos. No obstante, una función como inflate() no es probable que sea llamada con la frecuencia necesaria para que la diferencia sea palpable. En cualquier caso, el hecho de que las llamadas a función sean más concisas que los bucles, puede ayudar a prevenir errores de programación. Para dejar definitivamente la responsabilidad de la limpieza de los objetos sobre los hombros del programador cliente, se proporcionan dos formas de acceder a los punteros en PStash: el operador [], que devuelve el puntero sin eliminarlo del contenedor, y un segundo método remove() que además de devolver el puntero lo elimina del contenedor, poniendo a cero la posición que ocupaba. Cuando se produce la llamada al destructor de PStash, se prueba si han sido previamente retirados todos los punteros, si no es así, se notifica, de modo que es posible prevenir la fuga de memoria. Se verán otras soluciones mas elegantes en capítulos posteriores. Una prueba Aquí aparece el programa de prueba de Stash, reescrito para PStash: //: C13:PStashTest.cpp //{L} PStash // Test of pointer Stash #include "PStash.h" #include "../require.h" #include #include #include using namespace std; int main() { PStash intStash; // ’new’ works with built-in types, too. Note // the "pseudo-constructor" syntax: for(int i = 0; i < 25; i++) intStash.add(new int(i)); 386 ✐ ✐ ✐ ✐
✐ ✐ ✐ “Volumen1” — 2012/1/12 — 13:52 — page 387 — #425 ✐ 13.2. Rediseño de los ejemplos anteriores for(int j = 0; j < intStash.count(); j++) cout
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