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MOISES VILLENA MUÑOZ<br />
Cap 3 La Integral Definida<br />
b + T<br />
b<br />
=<br />
∫ ∫<br />
a + T<br />
a<br />
c. Si f es periódica con período T, <strong>en</strong>tonces: f ( x ) dx f ( x )<br />
b<br />
∫<br />
− a<br />
∫<br />
d. ∀ f , f ( − x ) dx = f ( x ) dx<br />
a<br />
e. Si es una función par<br />
−b<br />
f ∀ x ∈ [ −a,<br />
a]<br />
, <strong>en</strong>tonces f ( x ) dx = 2<br />
∫ ∫<br />
a<br />
− a<br />
f. Si f ( x) ≤ g( x)<br />
<strong>en</strong> [ a, b]<br />
, <strong>en</strong>tonces f ( x ) dx ≤ g ( x )<br />
g. Si F′ ( x) = G′<br />
( x) ∀x<br />
∈[ a,<br />
b] , F( b) − F( a) = G( b) − G( a)<br />
b<br />
∫<br />
a<br />
b<br />
∫<br />
a<br />
dx<br />
a<br />
0<br />
dx<br />
f ( x ) dx<br />
h. Sea g una función derivable y supóngase que F es una antiderivada de f . Entonces<br />
f ( g( x)<br />
) g′ ( x ) dx = F( g ( x ) ) + C<br />
∫<br />
3. Encu<strong>en</strong>tre f ′ si f toma las sigui<strong>en</strong>tes reglas de correspond<strong>en</strong>cia:<br />
s<strong>en</strong> x ln x<br />
1<br />
a. dt<br />
∫ 1 − t<br />
0<br />
3<br />
2 x sec<br />
3 5<br />
b. 1 − t dt<br />
ln x<br />
∫<br />
x<br />
e<br />
∫<br />
tanx<br />
3<br />
1<br />
c. dt<br />
2 − t<br />
x<br />
x<br />
e ln x sec x<br />
3<br />
x + s<strong>en</strong> x<br />
2 t<br />
4 5<br />
t − 1<br />
2<br />
x<br />
d.<br />
∫<br />
e.<br />
3<br />
x s<strong>en</strong><br />
ln<br />
6 log<br />
( tanx )<br />
∫<br />
2<br />
( x + 1)<br />
f.<br />
∫<br />
1 −<br />
x<br />
3<br />
2<br />
x<br />
2<br />
dt<br />
1 + s<strong>en</strong> t<br />
3<br />
1 − t<br />
cos t − s<strong>en</strong><br />
cos t<br />
dt<br />
t<br />
dt<br />
4. Determine:<br />
a.<br />
b.<br />
lim<br />
x → 0<br />
x<br />
∫<br />
0<br />
x<br />
∫<br />
lim 1<br />
s<strong>en</strong><br />
2<br />
( t )<br />
3<br />
x<br />
s<strong>en</strong>t dt<br />
+<br />
x → 1 x −<br />
1<br />
dt<br />
c.<br />
d.<br />
lim<br />
x→ ∞<br />
d<br />
dx<br />
⎡<br />
⎢<br />
⎢<br />
⎢<br />
⎣<br />
x<br />
x<br />
∫<br />
0<br />
1<br />
2<br />
∫<br />
1 + e<br />
x<br />
dt<br />
−t<br />
2<br />
⎤<br />
1−5t<br />
⎥ ⎥⎥ ⎦<br />
dt<br />
2<br />
60