Clase 4 2da parte - Pedeciba
Clase 4 2da parte - Pedeciba
Clase 4 2da parte - Pedeciba
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Relación entre concentración de sustrato y<br />
velocidad de reacción enzimática<br />
k 1 [E L ][S] = k -1 [ES] + k 2 [ES]<br />
k 1 [E T - ES][S] = k -1 [ES] + k 2 [ES]<br />
k 1 [E T ][S] – k 1 [ES][S] = k -1 [ES] + k 2 [ES]<br />
k 1 [E T ] [S] = k -1 [ES] + k 2 [ES] + k 1 [ES][S]<br />
k 1 [E T ] [S] = [ES] (k -1 + k 2 + k 1 [S])<br />
Dividimos por k 1 :<br />
[E T ] [S] = [ES] ((k -1 + k 2 ) + [S])<br />
k 1