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Apuntes para Capitán de yate - Los siete mares

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4. Un <strong>yate</strong> se encuentra con Cm = 2,80, ppG = 8,70 m., Epp = 19,00, ppC = 9,20,<br />

M u = 0,85, ∆ = 106 Tns., XF = 0,50 +. Calcular los calados.<br />

462<br />

Solución:<br />

pPp pPr<br />

8,70<br />

9,20<br />

XG – XC = 0,80 – 0,30 = 0,50 + = CG<br />

A × Mu = ∆ ×CG<br />

106 × 0,50<br />

A = = 62 cm.<br />

0,85<br />

A Pr =<br />

9,50<br />

A E ⎛ ⎞<br />

⎜ + XF⎟<br />

⎝ 2 ⎠ 62 × 10<br />

=<br />

E<br />

19<br />

App = 62 – 32,6 = 29,4 cm.<br />

Ci m = 2,8 Ci m = 2,8<br />

APr = 0,326– App = 0,294+<br />

CPr = 2,474 Cpp = 3,094<br />

G<br />

C<br />

19,00<br />

= 32, 6 cm.

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